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a = F/m = (8î + 2? )
r = ut + ½ at²
r = 0 + ½ (8î + 2? ) 10²
r = 400î + 100?

SGT University Online offers two-year MBA specilisation in Finance, Marketing, HR, Analytics, and others. The course is recognised by the UGC and accredited by NAAC A+ Grade. The university offers interactive coursework, real-time assistance, and a hands-on approach anchored through each learning experience.

The total tuition fee for the BSc programme at Bundelkhand University is INR 10.6 - 1.31 Lakh. The tuition fee is usually paid at the beginning of each academic year. Additionally, hostel facilities are also provided to students and the charges can cost around INR 26.4 K - 42.8 K. The total fee budget may also include admission charges, MBA application fees, and examination form fees.

g = (4/3)πRρG . (i) (ρ = density)
Now ρ = M/V = M/ (4/3)πR³)
R³ = M/ (4/3)πρ) => R ∝ (M/ρ)¹/³
From equation (i)
g ∝ Rρ ∝ (M/ρ)¹/³ρ = M¹/³ρ²/³
For planet, M' = 2M, ρ' = ρ
g'/g = (M'/M)¹/³ (ρ'/ρ)²/³ = (2)¹/³ (1)²/³ = 2¹/³
W' = mg' = m (2¹/³g) = 2¹/³ (mg) = 2¹/³W

Bundelkhand University BSc Fees 2025 includes different types of charges. The total tuition fee for the BSc programme is INR 10.6 - 1.31 Lakh. Tuition fee is usually paid at the beginning of each academic year. Hostel facilities are also provided to students and the charges can cost around INR 26.4 K - 42.8 K. The total fee budget may also include admission charges, MBA application fees, and examination form fees.

μ = sin (A + δm)/2) / sin (A/2)
Since, δm = A
μ = sin (A) / sin (A/2) = (2sin (A/2)cos (A/2) / sin (A/2)
μ = 2cos (A/2

For ball (a): I? = Δp? = 2mu
For ball (b): I? = Δp? = 2mu cos 45°
I? /I? = 2mu / (2mu cos 45°) = √2

By t = mx² + nx
dt/dx = 2mx + n
V = dx/dt = 1/ (2mx + n)
a = v (dv/dx) = V (d/dx (1/ (2mx+n) = V [-2m/ (2mx+n)²] = -2mV³
So, Retardation will be (2mv³)

I = I? cosωt
Current is changing from its maximum value to rms value (I? /√2)
I? /√2 = I? cosωt
cosωt = 1/√2
ωt = π/4
2π × 50t = π/4
t = 1/400 s = 2.5 ms

The application portal for ITM University Gwalior BPharma is open. Candidates seeking admission must apply for the preferred course by submitting the application form available on the university's official website. As per the admission schedule, the university is yet to release the last date. For more information, students can visit the university's official website.

Candidates may need to have the following details to download the AP LAWCET answer key-

• Candidates' roll number/ hall ticket number
• Registration number
• Mibile number

India Today, in partnership with the Marketing & Development Research Associates (MDRA), uses a comprehensive methodology to rank the BBA programme at the MIT-WPU, Pune. Some of the parameters that are widely considered by India Today while ranking BBA courses are Intake Quality & Governance, Academic excellence, Infrastructure & Living Experience, etc. 

tan 37° = E? /E?
E? = k (2p? /r³) axial direction
E? = k (p? /r³) equatorial direction
tan 37° = (k p? /r³) / (k 2p? /r³) = p? / (2p? ) = 3/4
p? /p? = 2/3

Yes, APSCHE releases the provisional answer key for the Andhra Pradesh LAWCET/ PGLCET exam at first for candidates to go through the same and raise objections, if any. The candidates will have to raise their dispute on the provisional answer key within a given deadline by paying a objection raising fee.

According to question
|x| = |y| and
|x - y| = n|x + y|
x² + y² - 2x·y = n² (x² + y² + 2x·y)
(1 - n²) (x² + y²) = (1 + n²)2x·y
(1 - n²) (x² + y²) = (1 + n²)2xy cosθ
(1 - n²) (2x²) = (1 + n²) (2x²)cosθ
cos θ = (1 - n²)/ (1 + n²)
θ = cos? ¹ (1 - n²)/ (1 + n²) = cos? ¹ (- (n²-1)/ (n²+1)

Currently, the ranking for the BBA course at MIT-WPU, Pune  has not been released. However, the course and institution have been ranked by the prestigious ranking bodies for consecutive academic years. Check out the ranking of BBA courses by different ranking bodies below:

For electron,
λe = h/p ⇒ (KE)e = ½mv² = p²/ (2m) = (h²/λ²)/ (2m)
For photon,
λp = h/p ⇒ (K.E.)p = pc = hc/λ
KEe / KEp = (h²/ (2mλ²) / (hc/λ) = h/ (2mcλ)
But for electron p = mv = h/λ so h/λ = mv
KEe / KEp = mv / (2mc) = v/2c