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The Gateway Institute of Hotel Management fees for BBA programme is affiliated to the Guwahati University and offered in the Hotel Management specialisation. The students need to pay the tuition fee against the course. The fee breakdown is given below:

NOTE: This information is sourced from the official website/sanctioning body and is subject to change. Given below are the key highlights for the Gateway Institute of Hotel Management BBA courses:

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

At Providence College of Engineering, students can pursue several courses in full-time mode. These programmes are provided in the fields of Engineering and management. Students are selected on an entrance basis for all of the offered courses, however, merit may also be considered in certain courses. Students can pursue the following courses at the college:

• BBA
• MBA
• BTech

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Thegivendifferentialequationis\\ \frac{dy}{dx}=\frac{1+y^2}{1+x^2}\\ \Rightarrow \frac{dy}{1+y^2}=\frac{dx}{1+x^2}\\ Integratingbothsides,weget\\ {\displaystyle \int \frac{dy}{1+y^2}={\displaystyle \int \frac{dx}{1+x^2}}}\\ \Rightarrow ta{n}^{-1}y=ta{n}^{-1}x+c\Rightarrow ta{n}^{-1}y-ta{n}^{-1}x=c\\ \Rightarrow ta{n}^{-1}\left(\frac{y-x}{1+xy}\right)=c\Rightarrow \frac{y-x}{1+xy}=tanc\\ \Rightarrow \frac{y-x}{1+xy}=k\left[?k=tanc\right]\\ \Rightarrow y-x=k\left(1+xy\right)\\ Hence,thecorrectoptionis\left(b\right).\end{array}$

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

Yes, you may get direct admission at Providence College of Engineering. Although the college mainly offers admissions on the basis of entrace exam scores, students may still apply under the management quota to get a seat at the college without appearing for any entrance exams. However, in such cases, fulfilling the admission criteria is essential. For more information, students can connect with the college's help desk.

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Thegivendifferentialequationis\\ \frac{dy}{dx}+y=e^{-x}\\ \text{\hspace{0.17em}since}itislineardifferentialequation\\ \therefore P=1andQ=e^{-x}\\ \therefore I.F.=e^{{\displaystyle \int 1.dx}}=e^x\\ So,thesolutionis\\ y\times I.F.={\displaystyle \int Q\times }I.F.dx+c\Rightarrow y\times e^x={\displaystyle \int e^{-x}}.e^{x}dx+c\\ \Rightarrow y\times e^x={\displaystyle \int 1.}dx+c\Rightarrow y.e^x=x+c\\ Putx=0,y=0,wehave0=0+c\therefore c=0\\ So,thesolutionisy.e^x=x\Rightarrow y=x.e^{-x}\\ Hence,thecorrectoptionis\left(b\right).\end{array}$

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}The\text{degree\hspace{0.17em}}ofthegivenDifferentialequationis1asthepowerofthehighestorderis1.\\ Hence,thecorrectoptionis\left(a\right).\end{array}$

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}ThegivenDifferentialequationis{e}^{x}cosydx-e^{x}sinydy=0\\ \Rightarrow e^x\left(cosydx-sinydy\right)=0\\ \Rightarrow cosydx-sinydy=0\left[?e^x\ne 0\right]\\ \Rightarrow sinydy=cosydx\\ \Rightarrow \frac{siny}{cosy}dy=dx\\ \therefore Integratingbothsides,weget\\ \Rightarrow {\displaystyle \int \frac{siny}{cosy}dy={\displaystyle \int dx}}\\ \Rightarrow -log\left|cosy\right|=x+logk\Rightarrow log\frac{1}{cosy}-logk=x\\ \Rightarrow log\left(\frac{1}{kcosy}\right)=x\Rightarrow \frac{1}{kcosy}=e^x\\ \Rightarrow \frac{1}{k}=e^{x}cosy\Rightarrow e^{x}cosy=c\left[?c=\frac{1}{k}\right]\\ Hence,thecorrectoptionis\left(a\right).\end{array}$

Students after pursuing BBA from Gateway Institute of Engineering and Technology has a variety of job profile option to choose from. The list given below shows the suitable job profiles:

• Marketing and Sales
• Finance and Accounting
• Human Resources
• Operations and Logistics
• Retail Management
• Administration and Management

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}ThegivenDifferentialequationisy\frac{dy}{dx}+x=c\\ \Rightarrow y\frac{dy}{dx}=c-xydy=\left(c-x\right)dx\\ \therefore Integratingbothsides,weget\\ \Rightarrow {\displaystyle \int ydy={\displaystyle \int \left(c-x\right)dx}}\\ \Rightarrow \frac{y^2}{2}=cx-\frac{x^2}{2}+k\\ \Rightarrow \frac{x^2}{2}+\frac{y^2}{2}-cx=k\\ \Rightarrow x^2+y^2-2cx=2kwhichisafamilyofcircles.\\ Hence,thecorrectoptionis\left(d\right).\end{array}$

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Thegivenequationista{n}^{-1}x+ta{n}^{-1}y=c\\ Differentiatingw.r.t.x,wehave\\ \Rightarrow \frac{1}{1+x^2}+\frac{1}{1+y^2}.\frac{dy}{dx}=0\\ \Rightarrow \left(\frac{1}{1+y^2}\right)\frac{dy}{dx}=-\left(\frac{1}{1+x^2}\right)\\ \Rightarrow \frac{dy}{dx}=-\left(\frac{1+y^2}{1+x^2}\right)\\ \Rightarrow \left(1+x^2\right)dy=-\left(1+y^2\right)dx\\ \Rightarrow \left(1+x^2\right)dy+\left(1+y^2\right)dx=0\\ Hence,thecorrectoptionis\left(c\right).\end{array}$

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:$\begin{array}{l}\end{array}$

For admission into BBA course provided by the Gateway Institute of Engineering and Technology, students have to meet the set eligibility criteria. The below table gives idea about the set eligibility criteria Gateway Institute of Engineering and Technology:

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}\text{second\hspace{0.17em}}orderdifferentialequationis{y}^{\text{'}}{y}^{\text{'}\text{'}}+y=sinx\\ Hence,thecorrectoptionis\left(b\right).\end{array}$