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NIT Surathkal cutoff 2025 was released for all rounds and categories belonging to the All India and Home State quota. The cutoff was declared in the form of opening and closing ranks for various BTech course specialisations. 

Students who belong to the General AI category need to attain a rank between 1528 and 31695. On the other hand, the General HS category cutoff range fell between 2726 and 50926. Please keep in mind that other categories will have different cutoffs accordingly. 

C= (2,3), O= (0,0). r = OC = √13.
Slope of OC = 3/2. Slope of PQ = -2/3.
Let P= (x, y). Vector CP = (x-2, y-3). Vector OC = (2,3).
CP.OC=0 ⇒ 2 (x-2)+3 (y-3)=0 ⇒ 2x+3y=13.
Also (x-2)²+ (y-3)²=13.
From 2x=13-3y, x= (13-3y)/2.
(13-3y)/2-2)²+ (y-3)²=13 ⇒ (9-3y)/2)²+ (y-3)²=13
(9 (y-3)²/4) + (y-3)² = 13 ⇒ (13/4) (y-3)²=13 ⇒ (y-3)²=4 ⇒ y-3=±2.
y=5 or y=1.
If y=5, x=-1. P= (-1,5).
If y=1, x=5. Q= (5,1).

Camellia Institute of Technology & Management courses are offered to students at the UG and Diploma levels. The college offers a BTech programme to students at the UG level for a duration of 4 years in full-time mode. The fee structure of the BTech programme at CITM Kolkata ranges between INR 3 Lacs and INR 3.5 lakh. 

Here's the CUET-PG Hindi syllabus:

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• ? ? ? ? (? ? ? ? ? )? ? ? ? ?
• ? ? ? ? ? ? ? (? ? ? ? ? ? ? ? ? )
• ? ? ? ? ? ?
• ? ? ? ? (? ? ? ? ? ? ? ? ? ? ? ? )
• ? ? ? (? ? ? ? ? ? ? ? ? )
• ? ? (? ? ? ? ? )

? P? =? P? ⇒ n!/ (n-r)! = n!/ (n-r-1)! ⇒ n-r=1.
? C? =? C? ⇒ r + (r-1) = n ⇒ n = 2r-1.
Substitute n: (2r-1)-r=1 ⇒ r=2.

Acharya N.G. Ranga Agricultural University provides good placements to its graduating students. The students are given excellent placement support every year placing them in top companies. Check out the table below to know the key highlights of the Acharya N.G. Ranga Agricultural University placements 2024:

NOTE: The above data is obtained from the NIRF report 2025

(2? -2) is multiple of 3.
If n is odd, 2? ≡ (-1)? =-1 (mod 3). 2? -2 ≡ -1-2 = -3 ≡ 0 (mod 3).
If n is even, 2? ≡ (-1)? =1 (mod 3). 2? -2 ≡ 1-2 = -1 (mod 3).
So n must be odd.
2-digit numbers are 10-99 (90 numbers).
Odd numbers are 11,13, .,99. Number of terms = (99-11)/2 + 1 = 45.
Probability = 45/90 = 1/2.

The institution has not released the course-wise placement packages as of yet. Meanwhile the NIRF report for MBA  has been released. Check out the table below to know more:

NOTE: The above data is obtained from the NIRF report 2025

For x>2, f (x) = ∫? ¹ (5+1-t)dt + ∫? ² (5+t-1)dt + ∫? (5+t-1)dt
= ∫? ¹ (6-t)dt + ∫? ² (4+t)dt + ∫? (4+t)dt
= [6t-t²/2]? ¹ + [4t+t²/2]? ² + [4t+t²/2]?
= (6-1/2) + (8+2 - (4+1/2) + (4x+x²/2 - (8+2)
= 5.5 + 5.5 + 4x+x²/2 - 10 = 4x+x²/2 + 1.
f (2? ) = 8+2+1 = 11. f (2? ) = 5 (2)+1 = 11. Continuous.
f' (x) = 4+x for x>2. f' (2? ) = 6.
For x<2, f' (x)=5. f' (2? )=5.
Not differentiable at x=2.

Yes, Acharya N.G. Ranga Agricultural University has an impressive placement record. The table below provides the placement data for the past three years as per the NIRF Report 2025:

NOTE: The above data is obtained from the NIRF report 2025

Adarsh Group of Institutions MBA Fees is a combination of multiple components. The tuition fee that costs around INR 6 Lacs is paid in installments at the beginning of each academic year. Besides, hostel fee that costs around INR 2.04 Lacs is also paid in installments each year. There are one-time payments such as admission fee and examination form fee which are also included in the total fees budget.

The institution has not released the overall average package. The median package offered at Acharya N.G. Ranga Agricultural University placements in recent years is present in the table below:

Circle: (x-1)² + (y-3)² = 4. C= (1,3), r=2.
Length of tangent from P (-1,1) is L = √ (-1)²+1²-2 (-1)-6 (1)+6) = √ (1+1+2-6+6) = √4 = 2.

Area of quadrilateral PACB = 2 * Area (PAC) = 2 * (1/2 * L * r) = 2*2=4.
AB is chord of contact. T=0 => -x+y- (x-1)-3 (y-1)+6=0 => -2x-2y+10=0 => x+y=5.
Distance of C from AB = |1+3-5|/√2 = 1/√2.
Length of AB = 2√ (r²-d²) = 2√ (4-1/2) = 2√ (7/2) = √14.
Area of ABD =?

The average package at Acharya N.G. Ranga Agricultural University Placement  has not been made available yet. However the median package has been released and is given in the table below:

NOTE: The above data is obtained from the NIRF report 2025

T? = ¹? C? (xsinα)¹? (acosα/x)? = ¹? C? x¹? ²? sin¹? α a? cos? α
For term independent of x, 10-2r=0 ⇒ r=5.
T? = ¹? C? sin? α a? cos? α = ¹? C? (sin2α/2)? a?
This is the greatest when sin2α=1.
the greatest value = ¹? C? (a/2)? = 10!/ (5!)².
¹? C? = 252.
252 (a/2)? = 252.
(a/2)? = 1 ⇒ a=2.