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Kindly consider the following Image

The most important topics for JEE Mains Maths, Physics and Chemistry are:

Tsinθ = qE
Tcosθ = mg
tanθ = qE/mg
E = V/d_eff. V = V? - (-V? ) = V? +V?
C? =kε? A/t, C? =ε? A/ (d-t).
Capacitors are in series. Q=C_eqV. E inside dielectric = σ/ (kε? ) = Q/ (Akε? ).
E in air = σ/ε? = Q/Aε?
Let's follow the solution.
Q = (C? / (C? +C? ) (V? +V? ).
E = E_air = Q/ (Aε? )
tanθ = qQ/ (Aε? mg) = q/ (Aε? mg) * (C? / (C? +C? ) (V? +V? )
Substitute C? and C?
This is getting complicated. The solution directly uses an expression for E. E = Q/C? Aε?

The selection process for the BBA course at NIFD Global, Indore, is primarily based on merit. The institute does not require an entrance exam for admission to this programme. Instead, applicants who have secured good scores in Class 12 can get admission according to their achieved scores in Higher Senior Secondary. 

Students who do not wish to join the offline coaching classes or do not have time can join online coaching or prepare self for the exam. Preparation for exam through online classes can be very effective when followed by a time-table and regular studies. Self study is also fine but only if you are self motivated and have good understanding of the topics covered in JEE Main syllabus. The best way to prepare will surely depend on students individual choice.

Kindly consider the following Image

P = Fv = (ma)v = m (dv/dt)v
P dt = mv dv
∫P dt = ∫mv dv
Pt = ½mv²
v = √ (2Pt/m)
dx/dt = √ (2P/m) t¹/²
x = √ (2P/m) ∫t¹/² dt = √ (2P/m) * (2/3)t³/²
Squaring to match options:
x² = (8P/9m) t³
This does not match. Let's re-examine the options.
Position x is proportional to t³/².
x = (8P/9m)¹/² t³/²

The primary eligibility requirement for admission to the BBA course at NIFD Global Indore is that applicants must complete their Class 12 from a respective board of education. Additionally, admission is based on merit, which is evaluated according to applicants' achieved scores in Class 12. The college accepts students from various boards, including CBSE, ISC, and MPBSE.

ω = 2πf = 1/√ (LC)
L = 1/ (4π²f²C) = 1/ (4π² * 60² * 0.1*10? ) = 70.3 mH

Yes, NIFD Global Indore does offer BBA courses for a duration of three years. The minimum eligibility requirement for admission to the BBA course is that applicants must complete their Class 12 from a recognised board of education, such as CBSE/ ICSE/ MPBSE, or equivalent. The institute offers a Bachelor of Business Administration (BBA) with a focus on Design Management and Retail Management. 

E? (due to A and G) = 2 * (kq/l²)cos (45) = √2 kq/l² (downwards)
E? (due to B and F) = 2 * (kq/l²)cos (45) = √2 kq/l² (towards left)
E? (due to C and H) = 0
E? (due to D and E) = 0
Resultant E = √ (E? ²+E? ²) = √ (2 (kq/l²)²+2 (kq/l²)²) = 2kq/l²
(Solution in the image seems to be different.)

BBA programme at MSRUAS comes with a total tuition fee of approximately INR 4.50 Lacs for the three-year duration. This fee covers six semesters of comprehensive academic learning, industry-focused training, and internships. Students can visit the official wesbite for more information.

T = 2π√ (m/k)
0.2 = 2π√ (0.5/k)
k = (0.5) (2π/0.2)² = 50π² ≈ 500
x = A sin (ωt) = 5 sin (2π/T * t)
At t=T/4, x = 5 sin (π/2) = 5cm
PE = ½kx² = ½ * 500 * (0.05)² = 250 * 0.0025 = 0.625 J

Energy of electron = 3 eV
It forms H atom in n=3 state. Energy released E = 3 - (-13.6/9) = 3 + 1.51 = 4.51 eV.
Photon Energy = 4.51 eV
Threshold energy = hc/λ = 12400eVÅ / 4000Å = 3.1 eV.
kE_max = 4.51 - 3.1 = 1.41 eV

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η_A = W_A/Q? = 1 - T/T?
η_B = W_B/Q? ' = 1 - T? /T
W_A = Q? (1 - T/T? ) = Q? - Q?
W_B = Q? ' (1 - T? /T) = Q? /2 (1 - T? /T)
Given W_A = W_B
Q? (1 - T/T? ) = (Q? /2) (1 - T? /T)
Q? (T? /T) (1-T/T? ) = (Q? /2) (1-T? /T)
(T? /T - 1) = (1/2) (1-T? /T)
2T? /T - 2 = 1 - T? /T
2T? /T + T? /T = 3
T = (2T? +T? )/3

Degrees of freedom (f) = 3 translational + 3 rotational + (2 × 4) vibrational = 14
γ = 1 + 2/f = 1 + 2/14 = 8/7
W = nR? T/ (γ-1) = (1 × 8.3 × (310-300)/ (8/7 - 1) = (83)/ (1/7) = 581 J
As W is positive, work is done by the gas. The solution says W<0, work done on the gas. This implies? T is negative. The question states temperature rises, so work is done on the gas. W = -582J.