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Yes, you may get direct admission at SRK Institute of Technology. The institute reserves a certain amount of seats under the management quota. These seats are reserved under the “Category B”.  30% of the seats will be filled in by the college as per the norms approved by the Government of Andhra Pradesh. However, students may still have to fulfil the basic eligibility set by the college/concerned authority. For more details, students may connect with the help desk of the college.

Aspirants who have passed a Bachelor of Technology/ Engineering from a recognised university in the concerned discipline AMIE/ AMIETE, similar qualifications recognised by UPSC as equivalent to BE/ BTech can apply for M.Tech at Raghu Engineering College. Candidates must hold the documents proving their eligibility for verification at the time of admission.

To get admission into the SRK Institute of Technology courses, students need to complete several steps. The first step is to go through the admission criteria of the desired programme. Eligible students can then proceed further by registering themselves on the admission portal of the accepted exam/ counselling or at the website itself (for direct admissions). Once a seat is offered, students need to go through document verification and pay the SRKIT Vijayawada admission fees as per the institute's guidelines.

The TSEC Mumbai BE admission process begins with an eligibility check. In this stage, students must check if they fulfil the eligibility criteria. As per the institute's admission policy, students seeking admission must have passed Class 12 with Physics and Mathematics as compulsory subjects along with one of Chemistry or Biotechnology, or another relevant subject. Moreover, students must have obtained at least 45% marks (at least 40% marks in case of backward class categories, EWS and PwD candidates belonging to Maharashtra State only).

Yes, Raghu Engineering College offers M.Tech for two-years at the PG level. The programme is spread across four semesters. The college offers M.Tech in various specialisations such as Computer Science, Power Electronics,  Embedded Systems & VLSI,  Machine Design, CAD CAM and Embedded Systems. Admission to M.Tech course is based on GATE score of the candidates.

38. For $\frac{-2}{7}$ ,  $x$ ,  $\frac{-7}{2}$ to be in G.P. we have the condition,

$\Rightarrow$ $\frac{x}{-2/7}=\frac{-7/2}{x}$

$\Rightarrow$ $x^2=\left(\frac{-7}{2}\right)\times \left(\frac{-2}{7}\right)$

$\Rightarrow$ $x^2=1$

$\Rightarrow$ $x=+1$

36. Given, a = 3

Let r be the common ratio of the G.P.

Then, a₄ = (a₂)²

$\Rightarrow$ar^4-1 =   (ar^2-1)²

$\Rightarrow$ ar³=  (ar)²

$\Rightarrow$ ar³=  a²r²

$\Rightarrow$ $\frac{r^3}{r^2}=\frac{a^2}{2}$

$\Rightarrow$ r = a = 3

$\therefore$ a₇ = ar^7-1  = ar⁶= (-3) (-3)⁶  = (-3)⁷ = -2187.

35. Let a and r be the first term and the common ratio between G.P.

So, a₅= p $\Rightarrow$ a r^t-1 $$ $$ = p $\Rightarrow$ ar⁴ = p

a₈ = q $\Rightarrow$ a r^8-1 =q $\Rightarrow$ ar⁷= q

a₁₁= r $\Rightarrow$ ar^11-1 = r $\Rightarrow$ ar¹⁰= 5

So, L.H.S. q^{2 =}  (ar⁷)² = a²r¹⁴

R.H. S. = p.s= (ar⁴) (ar)¹⁰ = a¹⁺¹ r⁴⁺¹⁰  = a²r¹⁴

$\therefore$ L.H.S. = R.H.S.

Candidates seeking admission to the TSEC Mumbai BE programme and belonging to the state of Maharashtra must appear for the MHT CET exam. The application fee for this exam for general/unreserved category students is INR 800. The application fee for reserved category and PwD candidates is INR 600. 

Note: The above-mentioned fee is as per the official sources. However, it is indicative and subject to change.

Yes, SRK Institute of Technology admissions are currently open for various courses. Students can visit the college's official website to obtain the latest admission-related information. Candidates are advised to go through the website or connect with the college's help desk to obtain all the relevant updates about the course of choice for better understanding.

34. Given, r=2

Let a be the first term,

Then, a₈= 92

$\Rightarrow$ ar^8-1=192

$\Rightarrow$a (2)⁷ = 192

$\Rightarrow$ a = $\frac{192}{2^7}=\frac{192}{128}=\frac{3}{2}$

so, a = $\frac{3}{\begin{array}{l}2\\ \end{array}}$

$\therefore$ a₁₂ = ar^12-1= $\begin{array}{l}\left(\frac{3}{2}\right)\\ \end{array}$ (2)¹¹ = 3 2^11-1

= 3×2¹⁰

= 31024

= 3072.

33. Here, a= $\frac{5}{2}$

=  $r=\frac{\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$4$}\right.}{\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}=\frac{1}{2}$

so, a_n =  ar^n-1

i.e  a₂₀=ar^20-1= $\left(\frac{5}{2}\right)\times {\left(\frac{1}{2}\right)}^{19}=\frac{5}{2}\times \frac{1}{2^{19}}=\frac{5}{2^{19+1}}=\frac{5}{2^{20}}$

and an= ar^n-1= $\left(\frac{5}{2}\right)\times {\left(\frac{1}{2}\right)}^{n-1}=\frac{5}{2}\times \frac{1}{2^{n-1}}=\frac{5}{2^{n-1+1}}=\frac{5}{2^n}$

The University of California Riverside  Campus requires GRE for the Biophysics graduate programme only. Other than the programme mentioned, the GRE test is optional. Although, the students are generally suggested to take GRE for making their application stronger and raising chances to be admitted to this university. 

A strong GRE score for the University of California RIverside Campus is considered above 310. However UCR does not have a sepcific cut-off for GRE. 

University of Southern California is known to be one of the leading recognised universities globally. According to the Shiksha Popularity Rankings, USC has received a rank of #91 in 2025. The world rankings of the university by different ranking bodies are given as follows:

Top courses include Aerospace Engineering, AI, Cybersecurity, Petroleum Engineering, and Biomedical Engineering.

Yes, there are scholarships offerred by Khalifa universities covers full or partial tuition, visa, textbooks, and monthly stipend. Candidates have to fulfill the scholarship requirements to avail the benefits.