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Yes, IIFT Kakinada considers scores in IPMAT for admission. Integrated Programme in Management Aptitude Test or IPMAT is conducted at national-level every year by IIM Indore. It is a gateway to get a seat in the IIFT IPM course. The test is conducted in online mode for two hours in English language. Aspirants who pass IPMAT with a good score can get admission provided they also meet the eligibility requirements. 

46. Let a be the first term and r be the common ratio of the G.P.

Then $a_1+a_2+a_3=16$

$a+ar+a{r}^2+16^{}$

$a\left(1+r+r^2\right)=16$ ………. I

Also $a_4+a_5+a_6=128$

$a{r}^3+a{r}^4+a{r}^5=128$

$a{r}^3\left(1+r+r^2\right)=128$ …… II

Dividing II and I we get,

$\frac{a{r}^3\left(1+r+r^2\right)}{a\left(1+r+r^2\right)}=\frac{128}{16}$

r³= 8

r³ = 2³

 r = 2 >1

So, putting r = 2 in I we get,

$a\left(1+2+2^2\right)=16$

$\Rightarrow$ $a\left(1+2+4\right)=16$

$\Rightarrow$ $a\left(7\right)=16$

$\Rightarrow$ $a=\frac{16}{7}$

And $s_x=\frac{a\left(r^n-1\right)}{r-1}$

$\Rightarrow$ $\frac{\frac{16}{7}\left(2^n-1\right)}{2-1}$

$\Rightarrow$ $\frac{16}{7}\left(2^n-1\right)$

Through the Unitedworld Institute of Management (UIM), Karnavati University offers a regular BBA (Hons) in over ten specialisations. Students enrolled in the flagship BBA course can choose one of the nine available specialisations. Further, three of the Karnavati University BBA (Hons) specialisations are offered in association with the top organisations as knowledge partners. Check out the following table for a list of all these specialisations:

The molecules of CO₂ are held together by weak van der Waals forces of attraction which can be easily overcome by collisions of the molecules at room temperature. Consequently, CO₂ is a gas.
On the other hand, silicon atom forms four single covalent bonds with O-atom which are tetrahedrally arranged and form a three-dimensional structure. Thus, SiO₂ is a high melting solid.

Carbon dioxide can be obtained as a solid in the form of dry ice by allowing the liquified CO₂ to expand rapidly.
Unlike ordinary ice it does not melt and hence does not wet the surface on which it is kept. Thus, it is called dry ice.

45. Given, a=3

$r=\frac{3^3}{3}=3$>1

If s_n=120

Then $\frac{a\left(r^n-1\right)}{r-1}=120$

$\Rightarrow$ $\frac{3\left(3^n-1\right)}{3-1}=120$

$\Rightarrow$ $\frac{3\left(3^n-1\right)}{2}=120$

$\Rightarrow$ $3^n-1=120\times \frac{2}{3}$

$\Rightarrow$3ⁿ= 80+1

$\Rightarrow$ 3ⁿ= 81

= 3ⁿ = 34

$\therefore r=4$

So, 120 is the sum of first 4 terms of the G.P

The catenation depends on the strength of the element-element bond. As we move down the group 14, the element-element bond energies decrease rapidly, viz. C–C (355 kJ mol–1), Si–Si (222 kJ mol–1), Ge–Ge (167 kJ mol–1) and Sn–Sn (155 kJ mol–1), so the tendency for catenation decreases in the order C > Si > Ge > Sn.

Carbon atoms have the tendency to linkwith one another through covalent bonds to form chains and rings. This property is calledcatenation. This is because C—C bonds are very strong.

44. Let the three terms of the G.P be $\frac{a}{r},a,ar.$

So, $\frac{a}{r}a.ar=1$

= $a^3=1$

= $a=1$

And $\frac{a}{r}+a+ar=\frac{39}{10}$

= $\frac{1}{r}+1+r=\frac{39}{10}$ (as a = 1)

= $\frac{1+r+r^2}{r}=\frac{39}{10}$

= $\left(r^2+r+1\right)\times 10=39\times r$

= $10r^2+10r+10=39r$

= $10r^2+10r-39r+10=0$

= $10r^2-29r+10=0$

= $10r^2-25r-4r+10=0$

= $5r\left(2r-5\right)-2\left(2r-5\right)=10$

$=\left(2x-5\right)\left(5r-2\right)=0$

= $\left(2x-5\right)=0$ or $\left(5r-2\right)=0$

= $r=\frac{5}{2}$ or $r=\frac{2}{5}$

When $a=1,$ $r=\frac{5}{2}$ the terms are,

 $\frac{1}{\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$2$}\right.},1,$ $1\times \frac{5}{2}=\frac{2}{5},1,\frac{5}{2}$

When $a=1,$ $r=\frac{2}{5}$ the terms are,

$\frac{1}{\raisebox{1ex}{$2$}\!\left/ \!\raisebox{-1ex}{$5$}\right.},$ 1, $1\times \frac{2}{5}=\frac{5}{2},$ 1, $\frac{2}{5}$

Boron shows anomalous behaviour due to small atomic size, high electronegativity, high ionization energy and absence of d-orbital of B

  (b) SiO₄^4- is the basic unit of all silicates.

The basic eligibility requirement for admission to MMS courses at TIMSR Pune is that candidates must complete their graduation with a minimum aggregate of 50% from a recognised university. Moreover, for the selection, the acceptance of entrance examinations differs according to the Maharashtra and Non-Maharashra candidates. Check out the below table for better understanding:

(a) Producer gas is a mixture of CO and N₂ in the ratio of 2 :1

In order to make a choice between the BBA course offered by Bharathiar University Distance Education and IDE-Madras University, students can compare the options based on significant factors such as fees and overall Shiksha rating. To help, presented below is a comparison between the BBA course at Bharathiar University Distance Education and IDE-Madras University based on fees and ratings:

Note: The abovementioned information is as per official sources. However, it is subject to change. Hence, it is indicative.

(d) CO₂ is regarded as anhydride of carbonic acid.

H₂CO₃ ————> H₂O + CO₂