Ask & Answer: India's Largest Education Community

With a Jharkhand Raksha Shakti University BSc degree, aspirants can find job opportunities in both public and private sectors. The graduates can find jobs in the field of IT and Software, Nursing, and Science. Moreover, the salary package varies based on the chosen course specialisation and job profile. Mentioned below are a few top job profiles along with the average salary package for an insight in Career Scope after BSc:

NOTE: The given average salary details are as per Ambitionbox.com.

32. For the inequality, 2x – 3y>6 the eqⁿ is 2x – 3y=6. We consider the table below to plot 2x – 3y=6.

$\begin{array}{l}x\\ y\end{array}|\begin{array}{l}0\\ -2\end{array}|\begin{array}{l}3\\ 0\end{array}|$

This line divides the xy-plane into half planer I and II. We select point (0,0) and check the correctness of the inequality.

2 × 0 – 3 × 0>6

0>6 which is false.

So, the solution region is II which does not includes the origin (0,0).

The dotted line indicates that the any point on the line does not satisfy the given inequality.

For the international undergraduate students who are on an F-1 visa, the two primary scholarships which offered at California Bay are given below - 

• The Global Honors Scholarship - USD 2,500 (INR 2.14 L) for one academic year
• The Global Excellence Scholarship - No tuition fee for students with a GPA of 3.3 or more 

Students must be enrolled full-time, exhibit financial need, and be competitive for both.

31. For the inequality x – y≤ 2 so the equation of line is x – y=2. We consider the table below to plat x – y=2

$\begin{array}{l}x\\ y\end{array}|\begin{array}{l}0\\ -2\end{array}|\begin{array}{l}2\\ 0\end{array}|$

This line divides the xy-plane into half planer I and II. We select point (0,0) and check the correctness of the inequality.

0 – 0 ≤ 2

0 ≤ 2 which is true.

So, the solution region is I which includes the origin (0,0). The continuous line also indicates that any point on the line also satisfy the given inequality.

In the state of Jharkhand, there are over 180 colleges/ universities that offer BSc programmes in different specialisations. The fee and selection criteria varies from one college to another. Mentioned below are a few of the UG course offering colleges/ universities:

• Rajendra Institute of Medical Sciences
• Arka Jain University
• St. Xavier's College
• Usha Martin University
• YBN University, etc.

The BA specialisations offered by JECRC University are as follows: 

1. BA French
2. BA German
3. BA Spanish 
4. BA Japanese
5. BA English

Students have atleast passed class 12 with a 60%. 

27. For inequality, x+y < 5, the equation of line is x+y = 5.

We consider the tableto plot x+y=5.

Graph of x+y = 5 is given as dotted line in fig 1. This lines divides by plane in two half planes I and II. We select a point not on the line, say (0,0) which lies in region I.

Since, 0+0 < 5

0 < 5 is true.

The solution region is I. (where origin (0,0) is included)

The dotted line indicates that any point on the line does not satisfy the given inequality.

Candidates wishing to for admission at Motherhood University can download the form from the university's website. Aspirants need to submit the form along with the below specified documents in the campus to apply for admission:

• Class 10 and Class 12 certificates and marksheets
• Domicile (for permanent residents of Uttarakhand)
• Migration certificate/ Transfer certificate
• Annual Income Certificate
• Character certificate
• 15 passport-size photographs
• Caste certificate (if applicable)
• Medical Fitness Certificate
• Pre-qualifying test score card (if any)
• Aadhaar card
• Proof of entitlement for a particular reservation category (SC/ ST/ OBC Certificate)

The total course fee at both the universities is cumulative of various components, such as tuition fee, security deposit, library fee, and more. Additionally, the fee can also vary based on the chosen BSc/ BSc (H) programme. The total tuition fees for BSc at JRSU is INR 49,500. For BSc at Central University of Jharkand, the total tuition fee amount is INR 80,300. As can be observed, the UG-level course is more affordable at the Jharkhand Raksha Shakti University.

However, the aspirants must note that the mentioned fee amount is as per the official website/ sanctioning body. It is still subject to changes and hence, is indicative. 

26. Let ‘x’ cm be the length of the shortest piece.

Then, the two other remaining length is.

(x + 3) cm and (2x). cm.

So, given that,

2x - (x + 3) ≥ 5 cm.

2x- x - 3 ≥ 5.

x ≥ 5 + 3

x ≥ 8.

And. total length ≤ 91 cm

x + (x + 3) + 2x ≤ 91

4x + 3 ≤ 91

4x + 3 ≤ 91 - 3

$\Rightarrow x\le \frac{88}{4}$

x ≤ 22.

? 8 ≤ x ≤ 22.

Hence the length of the shortest board is greater than or equal to 8 cm and less than or equal to 22 cm.

Yes, with 70% in Class 12, you have a fair chance of getting a seat in a government college, especially in B.Sc and other general courses where cut-offs usually range from 60% to 80% depending on state and competition. Admission will depend on your category, college reputation, and seat availability during counselling rounds.

The course fee for JECRC University BA programme is INR 90000 for an academic year. For an hons degree students need to pay a total fee of INR 3.6 lakh. The BA course fee is INR 2.7 Lacs for the entire three year course. 

25. Let x cm be the shortest side of the triangle.

Thus, the other 2 sides are “3x” cm and “3x - 2” cm

Given, perimeter of A triangle ≥ 61

x + 3x - 3x- 2 ≥ 61

7x - 21 ≥ 61

7x ≥ 61 + 21

$\Rightarrow x\ge \frac{82}{7}$

x ≥ 9.

The minimum length of the shortest side is 9 cm.

Yes, Motherhood University offers a four-year BPharm course at the UG level. The programme is spread across eight semesters. Candidates who have completed Class 12 with 50% aggregate (45% aggregate for SC/ ST) in PCM/ PCB are eligible to apply for BPharm. The university also offers lateral entry to the BPharm programme. 

The total number of seats available for BSc in Computer Application and Cybersecurity at JRSU is 50. Jharkhand Raksha Shakti University allot seats as per the sanctioned intake and performance in selection rounds. The university/ sanctioning body reserves the right to revise the seat intake in an academic year. It must be noted that the given intake is as per the official website/ sanctioning body. It is still subject to revision and hence, is indicative. 

24. Let x be the smaller no. of the two consecutive even positive integers, hence the other number is x + 2. (Two consecutive even no. differs by 2).

Then, x > 5, x + 2 > 5  => a> 3.

And x + (x + 2) < 23

2x + 2 < 23

2x < 23 - 2

2x < 21

$\Rightarrow x<\frac{21}{2}=10.5.$

So, 5 < x$\frac{21}{2},\; x\in z\; and\; x\; is\; positive.$

Hence, x can take the value 6, 8 and 10.

So, the required possible pair is given by (x, x + 2) are (6, 8), (8, 10) and (10, 12).

23. Let x be the smaller of the consecutive odd positive integers, then the. other is x + 2 {Since the consecutive odd number are differ by 2.}

then the. other is x + 2

so, x < 10 and x + 2 < 10 x< 8

and x + (x + 2) > 11.

2x > 11 - 2

2x > 9

$\Rightarrow x>\frac{9}{2}$

and hence,  $\frac{9}{2}<x<8$

4.5

As x ∈ z, x = 5 and x = 7 and x is odd

The reqd. possible pairs by (x, x + 2) are (5, 7), (7, 9).