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Yes, along with the tuition fee, colleges and universities generally charge students with exam, library, hostel, lab, etc., fees. Depending on the entity, these charges can be high or low. 

The BSc Nursing application fee depends on the college and the category of the candidate. However, it generally ranges between INR 1,000 to INR 5,000. 

Hi,

Yes, many BCom colleges in Hyderabad grant admission to students only through the CUET entrance exam. Here are some details about CUET:

Disclaimer: This info. is taken from the official website and may differ.

Though it completely depends on the individual institution's policies, it's highly unlikely you'll get a full refund on your college fees after 6 months in the program, as most colleges have policies that significantly deduct refund amounts after a certain period, especially when the classes have started.

Yes, BSc Nursing Scholarships in India are offered as an award for merit or as financial aid. These scholarships help students to pursue their BSc Nursing degrees without financial burden. Some popular scholarships for BSc Nursing include:

1. Lila Poonawala Scholarship 
2. ACC Vidyasaarthi Scholarship 
3. Mother Teresa Scholarship 
4. Timken Scholarship 
5. Casella Family Brands Health Overseas Scholarships 
6. UK's University of Salford Year of the Nurse and Midwife International Scholarship 

Yes, apart from the BSc Nursing tuition fees, many charges required to pay. Here are some additional charges you may find in your BSc Nursing course fee structure:

• Admission fee
• Enrollment fee
• Caution Money (Refundable at the end of the course)
• Examination fee
• Laboratory fee
• Library fee
• Student Welfare fund
• Extra Curricular Activities fee

Moreover, if you opt for a hostel during the program, then you'll be charged a hostel fee, security fee, hostel mess, etc., additionally.

Various aspects affect the BSc Nursing course fee of a college such as a college entity (government or private), college accreditation, demand, geographical location, faculty rating, government policies, placement rating, etc.

Sure! Students can learn more about the BCom colleges in Hyderabad by reading the table provided below:

Disclaimer: This info. is taken from the official website and may differ.

$\frac{2}{?4}=\frac{?1}{2}$

y – 4 = 2 (x – 3)

y = 2x – 2

x² + (2x – 2)² = 25

$5x^2?8x?21=0$

$z\left(\frac{?7}{5},\frac{?24}{5}\right)$

$t_n=\frac{3^n-2^n}{3^n}=1-{\left(\frac{2}{3}\right)}^n$

$S_{100}=100-\frac{\frac{2}{3}\left({\left(\frac{2}{3}\right)}^{100}-1\right)}{\frac{2}{3}-1}=100+2.\frac{\left(2^{100}-3^{100}\right)}{3^{100}}$

$=100-2+\frac{2^{101}}{3^{100}}=98+{\left(\frac{2}{3}\right)}^{100}.2<98+1$

$\left[\begin{array}{ccc}\hfill a_1\hfill & \hfill a_2\hfill & \hfill a_3\hfill \\ \hfill b_1\hfill & \hfill b_2\hfill & \hfill b_3\hfill \\ \hfill c_1\hfill & \hfill c_2\hfill & \hfill c_3\hfill \end{array}\right]a_1,b_1,c_{1}t\left\{-1,0,1\right\}$

$\underset{9times}{\underset{?}{a_1+a_2+a_3+....}}=5$

Total = 414

$\lambda =1+\mu$

$\begin{array}{l}\underset{\_}{2\lambda =3\lambda \mu }\\ \lambda =2\to S\left(2,4,6\right)\end{array}$

$\mu =1$

$\overrightarrow{n}=\left|\begin{array}{ccc}\hfill \widehat{i}\hfill & \hfill \widehat{j}\hfill & \hfill \widehat{k}\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill 3\hfill \\ \hfill 1\hfill & \hfill 1\hfill & \hfill 5\hfill \end{array}\right|=\left(7,-2,-1\right)$

7x – 2y – z + d = 0

(2, 4, 6) Þ d = -14 + 8 + 6

d = 0

7x – 2y – z = 0

7 – 2 = 5

Candidates can only attempt SET exam twice on given test dates. The SET exam 2026 will be conducted on May 2 and 10. 

Candidates can mention their number of attempts while filling the SET application form. However, they have to pay the application fee per session. Thus, candidates who are sure of making multiple attempts only they should apply for multiple sessions as the fee amount is non-refundable.  

g(1) = ?

    $=f\left(f\left(f\left(1\right)\right)\right)+f\left(f\left(1\right)\right)$            

$f\left(1\right)={\left(2\left(1-\frac{1}{2}\right)\left(2+1\right)\right)}^{\frac{1}{50}}=3^{\frac{1}{50}}$

  $3^{\frac{1}{50}}+13^{\frac{1}{50}}>1^{\frac{1}{50}}$             

3 > 1

$3^{\frac{1}{50}}>2$ $2>3^{\frac{1}{50}}>1$

$3<2^{50}$ $\left[3^{\frac{1}{50}}+1\right]=1+1=2$                     

${\alpha }_n=19^n-12^n$

$\frac{31{\alpha }_9-{\alpha }_{10}}{57.{\alpha }_2}=\frac{31\left(19^9-12^9\right)-\left(19^{10}-12^{10}\right)}{57\left(19^8-12^8\right)}$

$=\frac{19^9\left(31-19\right)-12^9\left(31-12\right)}{57\left(19^8-12^8\right)}$

$=\frac{19^9.12-12^9.19}{57\left(19^8-12^8\right)}=4$

SET application process 2026 has started. Last date to register for the exam was April 15, 2026. 

The SET exam application schedule was announced online. The SET exam application process begins with filling out the SET exam application form and proceeding on to the fee payment. Candidates need to submit their SET application form 2026 before the deadline. Candidates have to choose the their preferred institutes they wish to apply for admissions through SET exam score at the time of registration. Candidates are eligible for admission to only those institutes that they had selected in the SET application form.

Kindly consider the following answer

$\frac{\pi }{4}<x<\frac{\pi }{4}$

$\frac{14}{si{n}^{2}x}-2si{n}^{2}x=21-4+4si{n}^{2}x$

$t=\frac{-17\pm \sqrt[]{289+336}}{12}$

$=\frac{-17\pm 25}{12}=\frac{8}{12},\frac{-42}{12}$

$=\frac{2}{3},$

No. of solutions = 4

Kindly consider the following answer

$\frac{?}{4}<x<\frac{?}{4}$

$\frac{14}{si{n}^{2}x}?2si{n}^{2}x=21?4+4si{n}^{2}x$

$t=\frac{?17\pm \sqrt[]{289+336}}{12}$

$=\frac{?17\pm 25}{12}=\frac{8}{12},\frac{?42}{12}$

$=\frac{2}{3},$

No. of solutions = 4

$P\left(x_1,y_1\right)$

$Q\left(x_2,y_2\right)$

$x_1+x_2=\frac{r}{2},x_1{x}_2=\frac{P}{2}$

$y_1+y_2=s,y_1,y_2=-9$

$\left(x-x_1\right)\left(x-x_2\right)+\left(y-y_1\right)\left(y-y_2\right)=0$

$2\left(x^2+y^2\right)-rx-2sy+p-2q=0$

r = 11, s = 7, p – 2q = -22