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Moles of Br₂= moles of C₅H₁₀= $\frac{5}{60+10}=\frac{5}{70}$

$\therefore \frac{w}{160}=\frac{5}{70}$

$\therefore w=\frac{5\times 160}{70}=\frac{80}{7}g$

$=1142.8\times 10^{-2}\approx 1143\times 10^{-2}g$

As per popularity basis, listed below are the top BSW colleges in India along with their tuition fees:

Disclaimer: This information is sourced from the official website and may vary.

The BBA course at SRMCEM Lucknow is a three-year undergraduate course, divided into six semesters, and offered in full-time mode. Each semester is further divided into six months. Each month, students are required to complete and secure decent credits in the offered core and elective subjects. The whole detailed curriculum of the BBA course is available at the official website of the college. 

 ${\Delta }_t=\frac{hc}{\lambda }=\frac{6.63\times 10^{-34}\times 3.08\times 10^8}{600\times 10^{-9}}$

$=\frac{6.63\times 3.08\times 10^{-17}}{600}$ J

$=765.765\times 10^{-21}J$

$?766\times 10^{-21}$ J

$\frac{d\left[C\right]}{dt}=\left(\frac{20-10}{10}\right)=1mmold{m}^{-3}$

$+\frac{d\left[D\right]}{dt}=\left\{-\frac{d\left(B\right)}{dt}\right\}\times 1.5=\frac{3}{2}\left\{-\frac{d\left[B\right]}{dt}\right\}$

$\left\{-\frac{d\left[B\right]}{dt}\right\}=2\times \left\{\frac{-d\left[A\right]}{dt}\right\}$

$\therefore \frac{1}{6}\left\{\frac{-d\left[B\right]}{dt}\right\}=\frac{1}{3}\left\{\frac{-d\left[A\right]}{dt}\right\}=\frac{1}{9}\left\{\frac{+d\left[D\right]}{dt}\right\}=\frac{d\left[C\right]}{dt}$

$\therefore$ rate of reaction = $\frac{+d\left[C\right]}{dt}$ = 1m.m dm^-3 S^-1

Yes, Amrapali University Haldwani has prescribed both minimum and maximum age requirements for admission to its various UG courses, including BBA. Students who are aspiring to take admission must fulfil the below-mentioned age requirements:

• Minimum age requirement: 17 years of age
• Upper age limit: 25 years of age

 Note: The above information has been sourced from the official website. However, it is subject to change.

$F{e}^{+3}+l^{-}\to I_2+F{e}^{+2}$

Fe⁺² undergoes reduction & I₂ undergoes oxidation.

$E_{cell}^o=E_{cathode}^o-E_{anode}^o$

= (0.77 – 0.54) V = 0.23 V

= 23 × 10^-2 V

Yes, a BBA degree from Amrapali University makes students eligible for various jobs in government departments and organisations (both Central and State). There are many such jobs in government organisations that require skills learned during a BBA course. Tabulated below are some of the prospective government jobs along with their average salaries:

Note: The above-mentioned are industry-based average payouts. The actual salary may differ.

$N_2{O}_4?2N{O}_2$

$\underset{=0.5mol}{\left(1-0.5\right)}$ $2\times 0.5=1mol$

$k_P=\frac{{\left(\frac{1}{1.5}\times 1\right)}^2}{\left(\frac{0.5}{1.5}\times 1\right)}$

$=\frac{4}{3}=1.33$

$=-710.15J/mol$

No, Commerce subjects and streams are not compulsory for admission to the BBA course at SRMCEM Lucknow. The only primary eligibility required to get admission into the BBA course at SRMCEM Lucknow is that applicants must complete their Class 12 with a minimum of 50%. However, if an applicant is from Commerce stream, it is a plus point because in the entrance exam (LUACMAT), it gives 40% weightage to Commerce and Management in paper 1. Additionally, Numerical Aptitude/Elementary Maths carries 20% weight in paper 2. 

1000 ml solution contains 0.02 milli mole (mm)

$\therefore$ 500 ml solution contains 0.02 m.m

$\therefore$ Solution made 1000 ml with H₂O

$\therefore$ m.m in final solution = 0.01 mm

Solution (A) + 0.01 m. m H₂SO₄

= 0.01 + 0.01

= 0.02 m.m

= 0.00002 × 10³ mm

$\Delta H=-165kJ/mole$

T =?

$\Delta S=-550J{K}^{-1}$

At equilibrium ; $\Delta G=0$

$\therefore T=\frac{\Delta H}{\Delta S}=\frac{-165\times 1000}{-550}K$

$\begin{array}{l}=3\times 100K\\ =300K\end{array}$

Candidates aspiring to get admission to the Amrapali University BPharma course must fulfil the eligibility requirements. Only those who satisfy the requirements are considered for the selection process. Mentioned below is the common eligibility criteria for all candidates:

Eligibility: A pass in Class 10 and Class 12 with PCM/PCB/PCMB and English

$E_{1_H}=-2.2\times 10^{-18}J$

$Li\to L{i}^{+2}+2e^{-},n=2$

$E_{L{i}^{+2}}=E_{1H}\times \frac{Z^2}{n^2}=-2.2\times 10^{-18}\times \frac{3^2}{2^2}$

$\lambda =4\times 10^{-8}$ m

Molar mass of C₇H₅N₃O₆ = 12 × 7 + 1 × 5 + 14 × 3 + 16 × 6 = 84 + 42 + 96 = 227 g/mol

Number of moles = $\frac{681}{227}$  = 3 mol

$\therefore$ number of N-atoms

$=3\times 6.02\times 10^{23}\times 3=9\times 6.02\times 10^{23}$

$=5418\times 10^{21}$

$\therefore x=5418$ 

Looking at placement data from past years, it's clear that the SRM IST Vadapalani BBA and MBA placement is steadily improving. Back in 2022, the highest package offered to management students was around INR 12 LPA. In 2024, it rose to INR 16.13 LPA, suggesting strong recruiting. With the BBA 2025 batch approaching graduation, more competitive offers are expected.