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The Delhi Pharmaceutical Sciences and Research University has a total of 40 seats for the BSc in Biomedical Science programme. Candidates are admitted in the course as per the sanctioned intake. For seat allotment, the selection criteria is also taken into consideration. It must be noted that the mentioned seat intake is as per the official website/ sanctioning body. It is subject to changes and hence, is indicative.  

BDS full form in medical is Bachelor of Dental Surgery. The BDS course duration is 5 years, including four years of academic study and one year of compulsory internship. BDS course is a professional UG degree in Dentistry in India. Students can check the list of career options available after completing BDS from School of Dental Sciences (SDS), Sharda University:

DPSRU has a total of 180 seats for the BSc programmes. The seat allotment is done as per the sanctioned seat intake and the selection round. There might be reserved seats as well. However, the relevant documents also have to be submitted for the verification purposes. It must be noted that the mentioned seat count is as per the official website/ sanctioning body. It is still subject to revision and hence, is indicative.

School of Dental Sciences (SDS), Sharda University application forms are also available online. Candidates meeting the eligibility criteria can apply for the preferred course. Below are the steps to apply for admission:

Step 1: Visit the official SDS, SU website (medical.sharda.ac.in/).

Step 2: Fill out the details such as name, NEET score, NEET Roll No., etc.

Step 3: Complete the form and submit it. 

Yes, the University of Birmingham permits international students to work while studying. Overseas students must be mindful of the fact that they can work no more than 20 hours per week while classes are in session and it is essential that this employment does not interfere with a their academic program. During vacations, they can work for unlimited hours.

Know more about part-time jobs in UK for international students.

Yes, applications are open at School of Dental Sciences (SDS), Sharda University for various courses. The mode of application is online. Aspirants need to apply at the official website, i.e., medical.sharda.ac.in/ for admission to the various programme. Candidates can fill out the application form on the university's official website.

In order to get admission at School of Dental Sciences (SDS), Sharda University candidates must keep certain documents ready. Student can check the list of documents below:

• Scanned Class 10, Class 12 and graduation marksheet
• Leaving Certificate
• Aadhaar Card
• Passport-size photograph
• Signature

Note: The list of documents mentioned above are the general documents. For more details visit the official website.

Let x and y be the number of dolls of type A and B, respectively, that are produced in a week.

The given problem can be formulated as given below:

$Maximisez=12x+16y\dots \dots \dots ..\left(i\right)$

Subject to the constraints,

$\begin{array}{}\end{array}x+y \le 1200\dots \dots \dots \dots \left(ii\right)$

$y\le x/2orx\ge 2y\dots \dots \dots .(ii\mathrm{i)}$

$x–3y\le 600\dots \dots \dots \dots .\left(iv\right)$

$x,y\ge 0\dots \dots \dots \dots \dots \left(v\right)$

The feasible region determined by the system of constraints is given below:

A (600, 0), B (1050, 150) and C (800, 400) are the corner points of the feasible region.

The values of z at these corner points are given below:

The maximum value of z is 16000 at (800, 400).

Hence, 800 and 400 dolls of type A and type B should be produced, respectively, to get the maximum profit of? 16000.

Let the fruit grower use x bags of brand P and y bags of brand Q, respectively.

The problem can be formulated as given below:

$Maximisez=3x+3.5y\dots \dots \dots ..\left(i\right)$

Subject to the constraints,

$\begin{array}{}\end{array}x+2y \ge 240\dots \dots \dots ..\left(ii\right)$

$x+0.5y\ge 90\dots \dots \dots ..\left(iii\right)$

$1.5x+2y\le 310\dots \dots \dots ..\left(iv\right)$

$x,y\ge 0\dots \dots \dots \dots .\left(v\right)$

The feasible region determined by the system of constraints is given below:

A (140, 50), B (20, 140) and C (40, 100) are the corner points of the feasible region.

The values of z at these corner points are given below:

The maximum value of z is 595 at (140, 50).

Hence, 140 bags of brand P and 50 bags of brand Q should be used to maximise the amount of nitrogen.

Thus, the maximum amount of nitrogen added to the garden is 595 kg.

Let the fruit grower use x bags of brand P and y bags of brand Q, respectively.

The problem can be formulated as given below:

$Minimisez=3x+3.5y\dots \dots \dots \dots .\left(i\right)$

Subject to the constraints,

$\begin{array}{}\end{array}x+2y \ge 240\dots \dots \dots ..\left(ii\right)$

$x+0.5y\ge 90\dots \dots ..\left(iii\right)$

$1.5x+2y\le 310\dots \dots \dots ..\left(iv\right)$

$x,y\ge 0\dots \dots \dots \dots .\left(v\right)$

The feasible region determined by the system of constraints is given below:

A (240, 0), B (140, 50) and C (20, 140) are the corner points of the feasible region.

The values of z at these corner points are given below:

The maximum value of z is 470 at (40, 100).

Therefore, 40 bags of brand P and 100 bags of brand Q should be added to the garden to minimise the amount of nitrogen.

Hence, the minimum amount of nitrogen added to the garden is 470 kg.

As per the historical data of the university's alumni, most of the University of Birmingham graduates get placed in industries such as:

Joining the top ranked Pharmacy colleges in Delhi can be worthwhile for you. For that, you need to check its ROI. Listed below are some colleges along with their tuition fees and average placement package:

Disclaimer: This information is sourced from official website/ media reports/ NIRF website and may vary.

 During Jhulelal Institute of Technology placements the placement rate provided was 77.78%. Check out the table below to know more about the placement highlights at Jhulelal Institute of Technology:

According to 2024 official data, the minimum marks in Joint Entrance Examination advanced required to get into the Indian Institutes of Technology Patna is 4852 for General All India category candidates and 1939 for OBC All India category candidates. Candidates can further check category-wise IIT Patna JEE Advanced cutoff 2024 for  Mathematics and Computing Engineering specialisation in the table below: