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The Government College of Engineering BTech application form can be submitted online via the online admission portal. The steps to apply successfully are as follows:

1. Go to the official online admission portal.

2. Register by providing the required documents.

3. Log in with credentials generated in the earlier step.

4. Fill out the required details and pay the application fees.

5. Preview and submit.

Of course, the demand for Nursing professionals is high in the medical field, with a lot of job options in different departments in various healthcare facilities. MSc Nursing is a higher-level degree in the Nursing field, where not only do your chances of getting a higher salary increase, but you'll also get domain-specific knowledge and skills. 

r = î (1 + 12l) + j (-1) + k (l)
r = î (2 + m) + j (m - 1) + k (-m)
For intersection
1 + 2l = 2 + m
-1 = m - 1
l = -m
from (ii) m = 0
from (iii) l = 0
These values of m and l do not satisfy equation (1).
Hence the two lines do not intersect for any values of l and m.

Some good books for synonyms that will help students are as follows:

Sabarmati University, Ahmedabad, requires several documents to verify the eligibility and identity for BCom courses. The list of documents that are required at the time of filling out the application form is as follows:

• Class 10 and 12 Mark Sheets 
• Transfer Certificate
• Migration Certificate
• Character Certificate
• Caste or Category Certificate
• Domicile Certificate
• Passport-sized Photographs
• Identification Proof, etc. 

Government College of Engineering Aurangabad's fee structure for BTech courses includes various components such as tuition fees, examination fees, training fees, etc. As per the structure, the total tuition fee is INR 60,000. To know the other fees, candidates are advised to visit the official website of the institute.

 Note: The above-mentioned fee is as per the official sources. However, it is indicative and subject to change.

Let P = (3t², 6t); N = (3t²,0)
M = (3t², 3t)
Equation of MQ: y = 3t
∴ Q = (3/4 t², 3t)
Equation of NQ
y = ( 3t / (3/4 t² - 3t²) ) (x - 3t²)
y - intercept of NQ = 4t = 4/3 ⇒ t = 1/3
∴ MQ = 9/4 t² = 1/4
PN = 6t = 2

y² + ln (cos² x) = y x ∈ (-π/2, π/2)
for x = 0 y = 0 or 1
Differentiating wrt x
⇒ 2y' - 2tan x = y'
At (0,0)y' = 0
At (0,1)y' = 0
Differentiating wrt x
2yy' + 2 (y')² - 2sec² x = y'
At (0,0)y' = -2
At (0,1)y' = 2
∴ |y' (0)| = 2

To be eligible for the B.A. (Hons.) Journalism and Media Studies at JSJC, applicants must have completed the Class 12 in humanities, science, or commerce, with a minimum aggregate score of 60% from CBSE, ISC, State Boards, IB, Cambridge, or other government-recognised boards.

A: D ≥ 0
⇒ (m + 1)² - 4 (m + 4) ≥ 0
⇒ m² + 2m + 1 - 4m - 16 ≥ 0
⇒ m² - 2m - 15 ≥ 0
⇒ (m - 5) (m + 3) ≥ 0
⇒ m ∈ (-∞, -3] U [5, ∞)
∴ A = (-∞, -3] U [5, ∞)
B = [-3,5)
A − B = (-∞, −3) U [5, ∞)
A ∩ B = {-3}
B - A = (-3,5)
A U B = R

Ellipse: x²/4 + y²/3 = 1
eccentricity = √ (1 - 3/4) = 1/2
∴ foci = (±1,0)
For hyperbola, given 2a = √2 ⇒ a = 1/√2
∴ hyperbola will be x²/ (1/2) - y²/b² = 1
eccentricity = √ (1 + 2b²)
∴ foci = (±√ ( (1+2b²)/2 ), 0)
∴ Ellipse and hyperbola have same foci
√ ( (1+2b²)/2 ) = 1
⇒ b² = 1/2
∴ Equation of hyperbola: x²/ (1/2) - y²/ (1/2) = 1
⇒ x² - y² = 1/2
Clearly, (√3/2, 1/2) does not lie on it.

Burning of fossil fuels (which contain sulphur and nitrogenous matter) such as coal and oil in power stations and furnaces produce sulphur dioxide and nitrogen oxides which causes acid rain.