Ask & Answer: India's Largest Education Community

Fehling's solution is a complex of   $C{u}^{2+},C{u}^{2+}=3d^9$

No. of unpaired e^- = 1

MM =  $\sqrt[]{1\left(1+2\right)}=\sqrt[]{3}=1.73BM$

Joining IET Lucknow for BTech course is generally considered a good option. Candidates must consider factors like infrastructure, faculty experience, hostel and mess facilities, curriculum, etc. while taking admission. They can apply online or offline for admission at IET Lucknow.

Symbiosis Law School, Symbiosis International, Nagpur admissions are based on the entrance exam. Candidates must complete Class 12 and graduation as per the course requirements. To get admission at SLS Nagpur, candidates must meet the eligibility criteria set by the college. Once selected, candidates must pay the programme fee to confirm their seats in the institute.

SO₃ -> Sp² Planar

BF₃ -> Sp² Planar

$N{O}_3^{-}$ -> Sp² Planar

SF₄ -> Sp³d non-planar

H₂O₂ -> Sp³ Non-planar

PCl₃ -> Sp³ Non –planar

[Al (OH)₄]^{- ->} Sp³ Non-planar

XeF₄ -> Sp³d² planar

XeO₃ -> Sp³ Non-planar

$P{H}_4^{-}$ -> Sp³ Non-planar

Below are some BTech specialisations offered by IET Lucknow include- 

• Electrical Engineering
• Mechanical Engineering
• Civil Engineering
• Computer Science Engineering
• Electronics and Communication Engineering

  $2KMn{O}_4+3H_2{O}_2\underset{}{\overset{Basicmedium}{\to }}2Mn{O}_2+3O_2+2H_{2}O+2KOH$

Bauxite = AlOx (OH)_3-2x (where O < x < 1)

Siderite = FeCO₃

Cuprite = Cu₂O

Calamine = ZnCO₃

Haemetite = Fe₂O₃

Kaolinite = Al₂ (OH)₄Si₂O₅

Malachite = CuCO₃ Cu (OH)₂

Magneite = Fe₃O₄

Sphalerite = ZnS

Limonite = Fe₂O₃.3H₂O

The selection process is based on the entrance exam. No, to secure admission to BA LLB, BBA LLB and LLM courses at Symbiosis Law School, Symbiosis International, Nagpur, candidates must meet the college's eligibility criteria. For UG courses, aspirants must appear for SLAT and the All India Admission Test for the LLM course. 

The number of companies that visited the campus during SIBM Bangalore summer placements over the past three years is presented below:

$K=\frac{0.693}{t_{1/2}}=\frac{0.693}{70\times 60}=\frac{6930}{7\times 6}\times 10^{-6}$

= 165 × 10^-6 s^-1

The summer placement trend witnessed at SIBM Bangalore over the past three years is presented below:

C = 500   $\mu F,$ V = 100 v, L = 50 mH                                                        

In this LC – oscillation

q = q₀ cos   $\omega t$

$i=\frac{-dq}{dt}=q_0\omega sin\omega t\omega =\frac{1}{\sqrt[]{2c}}=\frac{1}{\sqrt[]{50\times 10^{-3}\times 5\times 10^{-4}}}$

=  $\frac{1000}{5}=200$  

So,     i_max =   $q_0\omega =500\times 10^6\times 100\times 200$

= 10A

$\frac{P^0-P_S}{P^0}=\frac{n_{solute}}{n_{solvent}}$

$\frac{P^0-\frac{P^0}{2}}{P^0}=\frac{n_{solute}}{n_{solvent}}$

$n_{solute}=\frac{n_{solvent}}{2}=\frac{100}{18\times 2}=2.78mol$

Pimpri Chinchwad College of Engineering and Research application forms are expected to be out soon as per various sources on the web. Interested students can connect with the college's help desk to learn about the exact timeline of the admission. The forms can be obtained from the college campus either in-person or via email.

The list of top recruiters during SIBM Bangalore placement 2025 is presented below:

Let x gm is burnt

Moles = x/280

Heat released by x/280 mol = 2.5 × 0.45 kJ

Heat released by 1 mol =  $\frac{2.5\times 0.45\times 280}{x}=kJ$

$\begin{array}{l}\Delta H=\Delta U+\Delta ngRT\\ \Delta H=\Delta U\end{array}$            

$9=\frac{2.5\times 280\times 0.45}{x}$            

x = 35 gm

After completing the MBA programme at Radha Govind University, students can explore a wide range of career paths across industries. Depending on their specialisation, they can pursue roles such as Marketing Manager, Financial Analyst, HR Manager, Operations Executive, Business Development Manager, or Project Coordinator. Top recruiters include Reliance, HDFC Bank, Flipkart, and Amazon, offering roles in both entry-level and mid-management positions.

For real gas under high pressure,

$Z=1+\frac{Pb}{RT}\Rightarrow b=\frac{RT}{P}=\frac{0.083\times 298}{99}$        

= 0.25 × 10^-2 L mol^-1

  ${\lambda }_A=25\lambda ,$ ${\lambda }_B=16\lambda$      

At t = 0 Þ N_A = N_B = N₀

after t =  $\frac{1}{a\lambda }:-\frac{N_B}{N_A}=\frac{N_0{e}^{-16\lambda t}}{N_0{e}^{-25\lambda t}}=e^{\left(25\lambda -16\lambda \right)t}$  

->e =  $e^{\left(9\lambda \frac{1}{a\lambda }\right)}$  

$\Rightarrow \frac{9}{a}=1\Rightarrow a=9$      

In the first semester of Radha Govind UniversityMBA programme, students build their foundational knowledge in management. The curriculum includes core subjects such as Principles and Practices of Management, Organizational Behavior, Financial Accounting, Managerial Economics, and Business Communication.