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$2B{F}_3+6NaH\to B_2{H}_6+6NaF$

$B_2{H}_6+2\ddot{N}{\left(Me\right)}_3\to 2H_{3}B\leftarrow :N{\left(Me\right)}_3$

Density of metal a very specific and depends upon many factors.

Li -> 0.53 gm/cm³

Na -> 0.97 gm/cm³

K -> 0.86 gm/cm³

Rb ->1.53 gm/cm³

Cs -> 1.90 gm/cm³

$2Mn{O}_4^{-}+6H^{+}+5H_2{O}_2\to 2M{n}^{2+}+8H_{2}O+5O_2$

$FeO+\underset{\left(Acidicflux\right)}{Si{O}_2}\to \underset{\left(Slag\right)}{FeSi{O}_3}$

IUPAC nomenclature of element with atomic no. 103 is uniltrium.

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$x=$ retentivity

$y=$ coercivity

$\mathrm{z}=$ saturation magnetization

Uses of catalyst is very specific for a particular reaction.

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$\left[N{H}_{4}Cl\right]=\frac{2}{60}=\frac{1}{30}M$

$pH=7-\frac{1}{2}P{K}_b-\frac{1}{2}logC$

$=7-\frac{5}{2}-\frac{1}{2}log\left(\frac{1}{30}\right)=5.24$

Yes, candidates who have passed their H.S.C. vocational examination may apply for admission to the B.Des program.

$\frac{\text{Energy}}{\text{Volume}}=\frac{{\mathrm{M}\mathrm{L}}^2{\mathrm{T}}^{-2}}{{\mathrm{L}}^3}=\left({\mathrm{M}\mathrm{L}}^{-1}{\mathrm{T}}^{-2}\right)$

 The distance between two successive bright fringes is fringe width $\left(\beta \right)$ .

$\beta =\frac{\lambda D}{d}=\frac{589\times {10}^{-9}\times 1.5}{0.15\times {10}^{-3}}=5.9\mathrm{m}\mathrm{m}$

Let we take $$ of solution

Mass of solute = Volume × Density

= 0.5 $m\mathcal{l}\times 1.05gm/m\mathcal{l}$ $$

= 0.525 gram

Mass of solution = 1 kg. [considering very dilute solution]

Mass of solvent = 1000 – 0.525 = 999.475 gram

$\Rightarrow i=1.9$

Yes, if you are from a non-English speaking background, most universities require some score in English language proficiency test. So, IELTS is not compulsory, you can attempt any other alternatives like TOEFL and PTE.

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Magnetic energy per unit volume $=\frac{{\mathrm{B}}^2}{2{?}_0}$

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