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It is estimated that joining the top Pharmacy colleges in Odisha might be affordable. Listed below are some colleges low-cost colleges along with their tuition fees:

Disclaimer: This information is sourced from official website/ media reports.

Resolving power

IILM Lucknow admissions are open for 2025 session. Interested candidates meeting the eligibility criteria can fill out the application form online or get it from the campus. IILM Lucknow offers admission to aspirants based on their entrance exam scores. The institute offers admission to BBA and PGDM programmes at UG and PG levels, respectively.

Kota University conducts the application process for various courses online. The application process for all the courses is INR 500. No application will be entertained in any condition after the last date of admission as given in the university notification. Check Kota University application process below:

 1: Visit the official website of the university.

2: Select the student admission tab

 3: Complete the form and submit.

  $S_1=\left\{z,\in c:\lfloor z_1-3\rfloor =\frac{1}{2}\right\}and{S}_2=\left\{z_2\in c:\left|z_2-\left|z_2+1\right|\right|=\left|z_2+\left|z_2-1\right|\right|\right\}$

Then, for $z_1\in S_1$  and $z_2\in S_2,$  the least value of |z₂ – z₁|

${\left|z_2+\left|z_2-1\right|\right|}^2={\left|z_2-\left|z_2+1\right|\right|}^2$      

$\Rightarrow \left(z_2+{\overline{z}}_2\right)\left(\left|z_2-1\right|+\left|z_2+1\right|-2\right)=0$      

$\therefore z_2+{\overline{z}}_2=0or\left|z_2-1\right|+\left|z_2+1\right|-2=0$          

$\therefore$ z₂ lies on imaginary axis or on real axis with in [-1, 1]

also $\left|z_1-3\right|=\frac{1}{2}$  lie on circle having centre 3 and radius   $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$

Clearly $\left|z_1-z_2\right|min=\frac{5}{2}-1=\frac{3}{2}$

Shri Krishna University BPharm and BPharm lateral fees is INR 3.52 Lacs and INR 2.64 lakh, respectively. The yearly fees is INR 88,100 for the UG programme. Once the final selection is done, aspirants have to pay the required fee amount to confirm their seats. It must be noted that the mentioned fee information is as per the official prospectus. Hence, is indicative.

$A^2=\left[\begin{array}{ccc}\hfill 0\hfill & \hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \end{array}\right]\left[\begin{array}{ccc}\hfill 0\hfill & \hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \end{array}\right]$

$=\left[\begin{array}{ccc}\hfill 0\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill & \hfill 0\hfill \end{array}\right]$

$a\leftrightarrow$ R2

$=-\left[\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 0\hfill & \hfill 1\hfill & \hfill 0\hfill \end{array}\right]$

$R_2\leftrightarrow R_3$

$=\left[\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 1\hfill \end{array}\right]$ =1 

$\begin{array}{l}{B}_0=A^{49}+2A^{98}=A+2I\\ B_n=Adj\left(B_n-1\right)\\ B_4=Adj\left(Adj\left(Adj\left(Adj{B}_0\right)\right)\right)\end{array}$

$={\left|B_0\right|}^{{\left(n-1\right)}^4}={\left|B_0\right|}^{16}$

$B_0=\left[\begin{array}{ccc}\hfill 0\hfill & \hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \end{array}\right]+\left[\begin{array}{ccc}\hfill 2\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 2\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill 2\hfill \end{array}\right]=\left[\begin{array}{ccc}\hfill 2\hfill & \hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 2\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 0\hfill & \hfill 2\hfill \end{array}\right]$

$=2\left(4-0\right)-1\left(0-1\right)=9$

$B_4{\left(9\right)}^{16}=3^{32}$

No, LLB programs are base level UG courses in the field of Law. You'll get the foundational knowledge of every Law specialisation at the LLB level but you cannot pursue LLB with a specific specialization. However, you can choose a specialisation at the PG level, i.e., LLM

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LLM.

$7^{2022}+3^{2022}$

$={\left(49\right)}^{1011}+{\left(9\right)}^{1011}$

$={\left(50-1\right)}^{1011}+{\left(10-1\right)}^{1011}$

$=5\lambda -1+5k-1$

= 5m – 2

Remainder = 5 – 2 = 3

Candidates seeking admission to Shri Krishna University BPharm course have to submit important documents for verification purposes. These are educational certificates and identity proofs. The necessary documents as per the 2025 prospectus are:

• Aadhaar card
• Admission form
• Class 10, 12 mark sheets
• Four passport-size photographs
• University specified declaration affidavit
• Original transfer certificate, CC and migration certificate

Yes, PhD course is available at Dr. DY Patil Dnyan Prasad University School of Hospitality & Tourism. The university offers PhD courses at the doctoral level. Candidate must meet the eligibility criteria to enrol for the PhD course admission set by the college. Aspirants must pass PG or equivalent in Hotel Management, Hospitality Management, Tourism Management, or any related stream. Dr. DY PDPUSHT's admission process is entrance-based.

$\frac{dy}{dx}+\left(\frac{2x^2+11x+13}{x^3+6x^2+11x+6}\right)y=\frac{x+3}{x+1},x>-1$

IF = $e^{{\displaystyle \int pdx}}=\frac{{\left(x+1\right)}^2\left(x+2\right)}{x+3}$

${\displaystyle \int Pdx={\displaystyle \int \frac{2x^2+11x+13}{x^3+6x^2+11x+6}dn={\displaystyle \int \left(\frac{2}{x+1}+\frac{1}{x+2}-\frac{1}{x+3}\right)dx}}}$

$=\mathcal{l}n\left({\left(x+1\right)}^2\cdot \left(x+2\right)/\left(x+3\right)\right)$

$\frac{2x^2+11x+13}{\left(x+1\right)\left(x+2\right)\left(x+3\right)}=\frac{A}{x+1}+\frac{B}{x+2}+\frac{C}{x+3}$

$2x^2+11x+13=A\left(x+2\right)\left(x+3\right)+B\left(x+1\right)\left(x+3\right)+C\left(x+1\right)\left(x+2\right)$

x = -1

->4 = 2A Þ A = 2

x = -2

-> -1 = -B Þ B = 1

x₂ – 3 Þ -2 = 2c

c = -1

$y\cdot \frac{{\left(x+1\right)}^2\left(x+2\right)}{x+3}={\displaystyle \int \frac{x+3}{x+1}\cdot \frac{{\left(x+1\right)}^2\left(x+2\right)}{x+3}dx}$

= ${\displaystyle \int \left(x+1\right)\left(x+2\right)dx}$

= $\frac{x^3}{3}+\frac{3x^2}{2}+2x+c$

$\left(0,1\right)\Rightarrow 1\cdot \frac{2}{3}=c$

x = 1  $y\cdot \left(3\right)=\frac{1}{3}+\frac{3}{2}+2+\frac{2}{3}=\frac{3}{2}+3=\frac{9}{2}$

y =  $\frac{3}{2}$

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Kota University admission to the undergraduate, postgraduate, doctoral-level, certificate & Diploma courses is based on the entrance/merit score of candidates. The duration of all the PG courses is two years each. The mode of application for all the courses is online.

For all the candidates seeking admission to various UG, PG, and doctoral courses, selection will be based on entrance exam-based or merit-based as per the course opted by the candidate. Scores of national and state-level exams are also considered for several courses.