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Given I = 2r

${\mu }_1=1\left(Air\right)$

${\mu }_2=\sqrt[]{2n}$

by, Snell’s law

$\mu sini={\mu }_{2}sinr$

$i=2co{s}^{-1}\left[\sqrt[]{\frac{n}{2}}\right]$

$V_0=\frac{1}{5}C$

$V_0=\frac{C}{5},V_S=0$

$f=f_0\left[\frac{C+V_0}{C+V_s}\right]$

V0 observer velocity

C sound velocity

Vs source velocity

$=\frac{\frac{6}{5}{f}_0-f_0}{f_0}\times 100$

$=\frac{1}{5}\times 100$

% change in frequency = 20%

$x=Asin\omega t$

Angle travelled by while moving from A to B

$\theta =30°=\frac{\pi °}{6}$

$\theta =\omega t$

$\frac{\pi }{6}=\omega \times 3\left[t=3sec\right]$

$\omega =\frac{\pi }{18}$

$\Rightarrow T=\frac{2\pi }{\omega }=\frac{2\pi \times 18}{\pi }=36sec$

T = 36 sec

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$\mathrm{}{\mathrm{M}\mathrm{A}}_2{\mathrm{B}}_2$ shows geometrical and not optical isomerism.

$F=qE\left[E=\frac{\sigma }{{\epsilon }_0}\right]$

$F=\frac{q\sigma }{{\in }_0}=10N$

Final case – Now one plate is removed, Electric field will becomes half; So, force will become half.

$F\text{'}=\frac{10}{2}=5N$

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Central University of South Bihar CUET cutoff 2025 has been released for admission to various UG courses. The cutoff has been released for different categories belonging to the All India quota. Among the General AI category candidates, the cutoff scores varied between 30 and 360.15. 

Among the OBC AI category candidates, the closing scores varied between 21 and 334.95. 

Candidates can check all the information such category-wise and round-wise cutoff on this page. 

The branch-wise cutoff for the General AI category candidates is given in the table below:

$\lambda =\frac{h}{mv}=\frac{h}{\sqrt[]{2MK.E}}$

$\lambda \alpha \frac{1}{\sqrt[]{m}}$

$\Rightarrow {\lambda }_{\alpha }\sqrt[]{m_{\alpha }}={\lambda }_{C_{12}}\sqrt[]{m_{C_{12}}}$

$\Rightarrow \frac{{\lambda }_{\alpha }}{{\lambda }_{C_{12}}}=\sqrt[]{\frac{m_{C_{12}}}{m_{\alpha }}}=\sqrt[]{\frac{12}{4}}=\sqrt[]{3}:1$

Carbon-chlorine bond cleavage is not possible in ${\mathrm{C}\mathrm{H}}_3=\mathrm{C}\mathrm{H}-\mathrm{C}\mathrm{l}$

Applicants are required to pay the application fee for BTech courses at the Central Agricultural University after completion of the application form. The application fee is INR 500, which is non-refundable. The fee amount mentioned is sourced from the official website/sanctioning body and is subject to change. Therefore, it is indicative.

All the courses offered by IIT Bhubaneswar offers good placements. The key highlights of IIT Bhubaneswar BTech and M.Tech placements 2025 are presented below:

Ultraviolet rays – sterilizing surgical instrument

Microwaves – Radar system

Infrared waves – Greenhouse effect

X-rays – Study crystal structure

The total fee of the BTech course at CAU might include different components, such as tuition fees, hostel fees, admission fees, etc. The total tuition fee for the BTech course is INR 2 lakh. The fee amount mentioned is sourced from the official website/sanctioning body and is subject to change. Therefore, it is indicative.

Given, I = 5 sin (120πt), $\omega$ $$ = 120

$T=\frac{2\pi }{\omega }$

$T=\frac{2\pi }{120\pi }=\frac{1}{60}sec,\frac{T}{4}=\frac{1}{60\times 4}=\frac{1}{240}sec$

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