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9 months ago

Atmiya University Placement Atmiya University

How many students were placed in the Atmiya University placements?

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diksha soni

Contributor-Level 10

A total of 2,661 students have been placed during the Atmiya University placements in the past three years. Check out the table below to see the breakdown of Students Placed (2024) in each year:

Particulars

Placement Statistics (2022)

Placement Statistics (2023)

Placement Statistics (2024)

Total Students

881 (UG 3-year)

356 (UG 4-year)

114 (PG 1-year)

476 (PG 2-year)

953 (UG 3-year)

318 (UG 4-year)

119 (PG 1-year)

456 (PG 2-year)

952 (UG 3-year)

251 (UG 4- year)

50 (PG 1-year)

473 (PG 2-year)

No. of Students Placed

298 (UG 3-year)

235 (UG 4-year)

56 (PG 1-year)

208 (PG 2-year)

310 (UG 3-year)

194 (UG 4-year)

68 (PG 1-year)

237 (PG 2-year)

455 (UG 3-year)

228 (UG 4-year)

29 (PG 1-year)

343 (PG 2-year)

NOTE: The above data is obtained from the NIRF report 2025

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Eleven

Find the distance of the point (2, 4, –1) from the line $\frac{4 - x}{2} = \frac{y}{6} = \frac{1 - z}{3} .$

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Ten

If $\vec{r}$ . $\vec{a}$ = 0, $\vec{r}$ . $\vec{b}$ = 0, $\vec{r}$ . $\vec{c}$ = 0 for some non-zero vector r̂, then the value of
( $\vec{a}$ × $\vec{b}$ ) ĉ is ________.

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alok kumar singh

Contributor-Level 10

This is a Fill in the blanks type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} I f \vec{r} i s a n o n - z e r o v e c t o r, t h e n \vec{a}, \vec{b} a n d \vec{c} c a n b e i n t h e s a m e p l a n e . \\ Since a n g l e s b e t w e e n \vec{a}, \vec{b} a n d \vec{c} a r e z e r o i . e . θ = 0 \\ ∴ \vec{a} . (\vec{b} \times \vec{c}) = 0 \\ H e n c e, t h e r e q u i r e d v a l u e i s 0 . \end{array}$

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9 months ago

Queen Mary University of London CITY, University of London

Which university is better: CITY University of London or Queen Mary University of London?

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Anangsha Singh

Contributor-Level 10

Both universities offer something unique for its international students to stand out of the herd. CITY University of London is located in London, UK and Brunel University is located in Middlesex, London, UK. Both the universities have their own advantages and disadvantages.

The CITY University of London acceptance rate stands at 52%, which makes it competitive to secure admission. Whereas, Brunel University acceptance rate stands at 70%, which makes it highly competitive to secure admission. Check the comparison listed below CITY University of London and Brunel University. This will surely help students in gaining more cl

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9 months ago

Atmiya University Atmiya University Placement

What is the reality of Atmiya University Placement?

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diksha soni

Contributor-Level 10

Atmiya University provides good placements to its graduating students. The students are given excellent placement support every year placing them in top companies. Check out the table below to know the key highlights of theAtmiya University Placement 2024:

Course	Total Students (2024)	Students Placed (2024)	Median Salary (2024)
UG 3-year	952	455	INR 2.50 LPA
UG 4-year	251	228	INR 3.60 LPA
PG 1-year	50	29	INR 1.80 LPA
PG 2-year	273	343	INR 2.40 LPA

NOTE: The above data is obtained from the NIRF report 2025

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9 months ago

Atmiya University Placement Atmiya University

How successful are the placements at Atmiya University?

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diksha soni

Contributor-Level 10

Atmiya University has been providing successful placements over the years. The students are given excellent placement support every year placing them in top companies. Check out the table below to know the key highlights of the Atmiya University Placement 2024:

Course	Total Students (2024)	Students Placed (2024)	Median Salary (2024)
UG 3-year	952	455	INR 2.50 LPA
UG 4-year	251	228	INR 3.60 LPA
PG 1-year	50	29	INR 1.80 LPA
PG 2-year	273	343	INR 2.40 LPA

NOTE: The above data is obtained from the NIRF report 2025

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Ten

The vector $\vec{a}$ + $\vec{b}$ bisects the angle between the non-collinear vectors $\vec{a}$ and $\vec{b}$ if ________.

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alok kumar singh

Contributor-Level 10

This is a Fill in the blanks type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} I f v e c t o r \vec{a} + \vec{b} bisects t h e a n g l e b e t w e e n n o n - c o l l i n e a r v e c t o r s \vec{a} a n d \vec{b} t h e n t h e a n g l e b e t w e e n \\ \vec{a} + \vec{b} a n d \vec{a} i s e q u a l t o t h e a n g l e b e t w e e n \vec{a} + \vec{b} a n d \vec{b} . \\ S o, c o s θ = \frac{\vec{a} . (\vec{a} + \vec{b})}{| \vec{a} | | \vec{a} + \vec{b} |} = \frac{\vec{a} . (\vec{a} + \vec{b})}{| \vec{a} | \sqrt[]{a^{2} + b^{2}}} \dots (i) \\ A l s o, c o s θ = \frac{\vec{b} . (\vec{a} + \vec{b})}{| \vec{b} | | \vec{a} + \vec{b} |} [? θ i s s a m e] \\ = \frac{\vec{b} . (\vec{a} + \vec{b})}{| \vec{b} | \sqrt[]{a^{2} + b^{2}}} \dots (i i) \\ F r o m e q . (i) a n d e q . (i i) w e g e t, \\ \frac{\vec{a} . (\vec{a} + \vec{b})}{| \vec{a} | \sqrt[]{a^{2} + b^{2}}} = \frac{\vec{b} . (\vec{a} + \vec{b})}{| \vec{b} | \sqrt[]{a^{2} + b^{2}}} \\ \Rightarrow \frac{\vec{a}}{| \vec{a} |} = \frac{\vec{b}}{| \vec{b} |} \\ \Rightarrow \hat{a} = \hat{b} \Rightarrow \vec{a} = \vec{b} \\ H e n c e, t h e r e q u i r e d f i l l e r i s \vec{a} = \vec{b} . \end{array}$

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9 months ago

Atmiya University Placement Atmiya University

Is Atmiya University good in terms of placements?

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diksha soni

Contributor-Level 10

Course	Total Students (2024)	Students Placed (2024)	Median Salary (2024)
UG 3-year	952	455	INR 2.50 LPA
UG 4-year	251	228	INR 3.60 LPA
PG 1-year	50	29	INR 1.80 LPA
PG 2-year	273	343	INR 2.40 LPA

NOTE: The above data is obtained from the NIRF report 2025

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9 months ago

Government Physiotheraphy College, Ahmedabad Physiotherapy

My age is 23 right now. Am I eligible to pursue BPT from Government Physiotheraphy College, Ahmedabad?

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Ten

The number of unit vectors perpendicular to both $\vec{a} = 2 \hat{i} + 2 \hat{j} + \hat{k}, \vec{b} = \hat{j} + 2 \hat{k}$ is:

(A) One

(B) Two

(C) Three

(D) Infinite

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

This is an Objective type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} T h e n u m b e r o f v e c t o r s o f u n i t l e n g t h p e r p e n d i c u l a r t o v e c t o r s \vec{a} a n d \vec{b} i s \vec{c} (L e t) \\ ∴ \vec{c} = \pm (\vec{a} \times \vec{b}) \\ S o, t h e r e w i l l b e t w o v e c t o r s o f u n i t l e n g t h p e r p e n d i c u l a r t o v e c t o r s \vec{a} a n d \vec{b} . \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Eleven

Find the foot of the perpendicular from the point (2, 3, –8) to the line $\frac{4 - x}{2} = \frac{y}{6} = \frac{1 - z}{3} .$ Also, find the perpendicular distance from the given point to the line.

0 Follower 8 Views

Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

$\begin{array}{l} G i v e n t h a t \frac{4 - x}{2} + \frac{y}{6} + \frac{1 - z}{3} i s t h e e q u a t i o n o f l i n e \\ \Rightarrow \frac{x - 4}{- 2} + \frac{y}{6} + \frac{z - 1}{- 3} = λ \\ ∴ C o o r d i n a t e s o f a n y point Q o n t h e l i n e a r e \\ x = - 2 λ + 4, y = 6 λ a n d z = - 3 λ + 1 \\ a n d t h e g i v e n point i s P (2, 3, - 8) \\ D i r e c t i o n r a t i o s o f P Q a r e - 2 λ + 4 - 2, 6 λ - 3, - 3 λ + 1 + 8 \\ a n d t h e D' r a t i o s o f t h e g i v e n l i n e a r e - 2, 6, - 3 . \\ I f P Q ⊥ l i n e \\ t h e n - 2 (- 2 λ + 2) + 6 (6 λ - 3) - 3 (- 3 λ + 9) = 0 \\ \Rightarrow 4 λ - 4 + 36 λ - 18 + 9 λ - 27 = 0 \\ \Rightarrow 49 λ - 49 = 0 \Rightarrow λ = 1 \\ ∴ T h e f o o t o f t h e p e r p e n d i c u l a r i s - 2 (1) + 4, 6 (1), - 3 (1) + 1 \\ i . e ., 2, 6, - 2 \\ N o w, distance P Q = \sqrt[]{{(2 - 2)}^{2} + {(3 - 6)}^{2} + {(- 8 + 2)}^{2}} \\ = \sqrt[]{9 + 36} = \sqrt[]{45} = 3 \sqrt[]{5} \\ H e n c e, t h e r e q u i r e d c o o r d i n a t e s o f t h e f o o t o f t h e p e r p e n d i c u l a r a r e 2, 6, - 2 a n d t h e \\ r e q u i r e d distance 3 \sqrt[]{5} u n i t s . \end{array}$

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9 months ago

Silver Oak University btech

What documents are required for BTech admission at Silver Oak University?

0 Follower 4 Views

Chikat Marchang

Contributor-Level 8

In order to get admission to the BTech course at Silver Oak University, students need to submit multiple documents. Students are advised to visit the official website to learn more about document submission. Furthermore, candidates can check the points mentioned below for document requirements to get admission to Silver Oak University:

Valid Mobile no. and email ID.
Class 10 and class 12 pass certificate.
Leaving certificate.
Aadhaar card.
Passport-size photo.
Signature.
Entrance Exam Scorecard (JEE Main or GUJCET).
Category Certificate (If Applicable).

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9 months ago

Silver Oak University B.Tech

What is the final step of the BTech admission process at Silver Oak University?

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Himanshu Singh

Contributor-Level 10

After being selected based on their entrance exam scores and eligibility, candidates must confirm their admission by paying the tuition fee. The BTech tuition fee at Silver Oak University ranges from INR 2.4 Lacs to INR 3.2 Lakh. Fee payment is the final step that secures a candidate's seat in the programme.

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Ten

If $∣ \vec{a} ∣ = 4$ and $- 3 \leq λ \leq 2$ , then the range of $∣ λ \vec{a} ∣$ is:

(A) [0, 8]

(B) [-12, 8]

(C) [0, 12]

(D) [8, 12]

0 Follower 8 Views

alok kumar singh

Contributor-Level 10

This is an Objective type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} G i v e n t h a t | \vec{a} | = 4, - 3 \leq λ \leq 2 \\ N o w | λ \vec{a} | = λ | \vec{a} | = λ . 4 = 4 λ \\ H e r e, - 3 \leq λ \leq 2 \\ \Rightarrow - 3.4 \leq 4 λ \leq 2.4 \Rightarrow - 12 \leq 4 λ \leq 8 \\ ∴ 4 λ = [- 12, 8] \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Eleven

Find the foot of the perpendicular from the point (2, 3, –8) to the line $\frac{4 - x}{2} = \frac{y}{6} = \frac{1 - z}{3} .$ Also, find the perpendicular distance from the given point to the line.

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

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9 months ago

Silver Oak University btech Eligibility

What is the selection criteria for BTech admission at Silver Oak University?

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Himanshu Singh

Contributor-Level 10

BTech admission at Silver Oak University is based on performance in entrance exams like JEE Main or GUJCET. Candidates must meet the eligibility requirements and secure a valid score in either exam. Selection is purely merit-based, with preference given to candidates who fulfill all academic and entrance criteria.

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9 months ago

Silver Oak University btech

How can I apply for the BTech programme at Silver Oak University?

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Ten

If $\vec{a}, \vec{b}, \vec{c}$ are three vectors such that $\vec{a} + \vec{b} + \vec{c} = 0$ and $? \vec{a} | = 2$ , $? \vec{b} | = 2, ? \vec{c} | = 2$ then the value of $\vec{a .} \vec{b} + \vec{b} . \vec{c} + \vec{c} . \vec{a}$ is:

(A) 0

(B) 1

(C) $- 19$

(D) 38

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alok kumar singh

Contributor-Level 10

This is an Objective type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} G i v e n t h a t | \vec{a} | = 2, | \vec{b} | = 3, | \vec{c} | = 5 \\ a n d \vec{a} + \vec{b} + \vec{c} = \vec{0} \\ ∴ (\vec{a} + \vec{b} + \vec{c}) . (\vec{a} + \vec{b} + \vec{c}) = \vec{0} . \vec{0} = 0 \\ {| \vec{a} |}^{2} + \vec{a} . \vec{b} + \vec{a} . \vec{c} + \vec{b} . \vec{a} + {| \vec{b} |}^{2} + \vec{b} . \vec{c} + \vec{c} . \vec{a} + \vec{c} . \vec{b} + {| \vec{c} |}^{2} = 0 \\ \Rightarrow {| \vec{a} |}^{2} + {| \vec{b} |}^{2} + {| \vec{c} |}^{2} + 2 \vec{a} . \vec{b} + 2 \vec{b} . \vec{c} + 2 \vec{c} . \vec{a} = 0 \\ \Rightarrow {(2)}^{2} + {(3)}^{2} + {(5)}^{2} + 2 (\vec{a} . \vec{b} + \vec{b} . \vec{c} + \vec{c} . \vec{a}) = 0 \\ \Rightarrow 4 + 9 + 25 + 2 (\vec{a} . \vec{b} + \vec{b} . \vec{c} + \vec{c} . \vec{a}) = 0 \\ \Rightarrow 38 + 2 (\vec{a} . \vec{b} + \vec{b} . \vec{c} + \vec{c} . \vec{a}) = 0 \\ \Rightarrow 2 (\vec{a} . \vec{b} + \vec{b} . \vec{c} + \vec{c} . \vec{a}) = - 38 \\ \Rightarrow \vec{a} . \vec{b} + \vec{b} . \vec{c} + \vec{c} . \vec{a} = - 19 \\ H e n c e, t h e c o r r e c t o p t i o n i s (c) . \end{array}$

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9 months ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 12th Chapter Eleven

Two systems of rectangular axes have the same origin. If a plane cuts them at distances a, b, c and a′, b′, c′, respectively, from the origin, prove that $\frac{1}{a^{2}} + \frac{1}{b^{2}} + \frac{1}{c^{2}} = \frac{1}{a ’^{2}} + \frac{1}{b ’^{2}} + \frac{1}{c ’^{2}} .$

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t O X, O Y, O Z a n d o x, o y, o z b e t w o rectangular s y s t e m s \\ ∴ E q u a t i o n s o f t w o p l a n e s a r e \\ \frac{X}{a}, \frac{Y}{b}, \frac{Z}{c} = 1 \dots (i) a n d \frac{x}{a^{'}}, \frac{y}{b^{'}}, \frac{z}{c^{'}} = 1 \dots (i i) \\ L e n g t h o f p e r p e n d i c u l a r f r o m o r i g i n t o p l a n e (i) i s \\ = \frac{\frac{0}{a} + \frac{0}{b} + \frac{0}{c} - 1}{\sqrt[]{\frac{1}{a^{2}} + \frac{1}{b^{2}} + \frac{1}{c^{2}}}} = \frac{1}{\sqrt[]{\frac{1}{a^{2}} + \frac{1}{b^{2}} + \frac{1}{c^{2}}}} \\ L e n g t h o f p e r p e n d i c u l a r f r o m o r i g i n t o p l a n e (i i) i s \\ = \frac{\frac{0}{a^{'}} + \frac{0}{b^{'}} + \frac{0}{c^{'}} - 1}{\sqrt[]{\frac{1}{{a^{'}}^{2}} + \frac{1}{{b^{'}}^{2}} + \frac{1}{{c^{'}}^{2}}}} = \frac{1}{\sqrt[]{\frac{1}{{a^{'}}^{2}} + \frac{1}{{b^{'}}^{2}} + \frac{1}{{c^{'}}^{2}}}} \\ A s p e r t h e c o n d i t i o n o f t h e q u e s t i o n \\ \frac{1}{\sqrt[]{\frac{1}{a^{2}} + \frac{1}{b^{2}} + \frac{1}{c^{2}}}} = \frac{1}{\sqrt[]{\frac{1}{{a^{'}}^{2}} + \frac{1}{{b^{'}}^{2}} + \frac{1}{{c^{'}}^{2}}}} \\ H e n c e, \frac{1}{a^{2}} + \frac{1}{b^{2}} + \frac{1}{c^{2}} = \frac{1}{{a^{'}}^{2}} + \frac{1}{{b^{'}}^{2}} + \frac{1}{{c^{'}}^{2}} \end{array}$

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9 months ago

Northern Arizona University Study Abroad

How big is the NAU enrollment?

0 Follower 2 Views

Ridhi

Contributor-Level 10

The total number of enrollments at the Northern Arizona University stands at 28,468, of which 22,991 are undergraduates while 5,477 are graduates. For Fall 2024, the university had 4,900 UG enrollments. The NAU admission statistics, along with the acceptance rate trends are given below for the reference of students:

Particulars	2024-2025	2023-2024	2022-2023	2021-2022	2020-2021
Application Received	35,100	37,805	44,885	42,872	37,386
Admitted Students	31,453	34,383	35,881	33,592	30,523
Acceptance Rate	89.61%	90.95%	79.94%	78.35%	81.64%

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Parameters	CITY University of London	Brunel University
Shiksha Popularity Rankings	#268 in World	#240 in World
Establishment	1884	1966
Location	London, UK	Middlesex, London, UK
University Type	Public	Public
University Ratings on Shiksha (Out of 5)	4.3	4.2
Acceptance Rate	52%	70%
Placement Rate	93%	94%
QS Rankings 2026	#310	#385
Average Salary	INR 39.96 LPA	INR 33.80 LPA
UG Annual Tuition Fee	INR 17.04 L - 34.88 L	INR 17.26 L - 56.12 L
PG Annual Tuition Fee	INR 1.39 L - 57.26 L	INR 17.26 L - 56.12 L
Popular Streams	Psychology \| Computer Science \| MBA	International Business \| Accounting \| Artificial Intelligence MSc

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