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It is actually different for everyone since everyone has their own speed. It also depends on the paper- if its lengthy or not. There is a Cool-off time of 15 minutes in addition to the writing time. Use the 'Cool-off time' to get familiar with questions and to plan your answers. Read questions carefully before answering. Read the instructions carefully and you can analyze your entire question paper no matter which subject is it, and mentally set time for each sections. Since there are mcqs too, you can solve them in the 15 mins cool off time and thus save you a lot of time.

A total of 116 students got placed during CIMP placements 2025 for the PGDM course. Refer to the table below for more information details about PGDM placements 2025 at Chandragupt Institute of Management.

$I=I_{0}co{s}^{2}30°$

$=I_0{\left(\frac{\sqrt[]{3}}{2}\right)}^2=\frac{3}{4}{I}_0$ 

The Chandragupt Institute of Management offers excellent salary packages to its student. Please refer to the table below for more details about CIMP Placement 2025.

The Chandragupt Institute of Management placement's the highest package stood at INR 16.4 LPA. Check out the table to know the same:

Find total (5 digit) number of divisors of 7. Find total (5 digit) number of divisors of 35

Elastic deformation leads to the temporary change in a material's shape that is also reversible. It occurs for energy storage in devices, such as springs. It's also essential for understanding the flexibility of structural components like beams in bridges. This principle is used in engineering design. You can think vehicle suspension systems and even the resilience of buildings against wind forces.

v = 100 sin $\omega t$

$i_0=\frac{100}{R_x}=5\Rightarrow R_x=20\Omega$

i = $5sin\left(\omega t-\raisebox{1ex}{$\pi $}\!\left/ \!\raisebox{-1ex}{$2$}\right.\right)$

i = 100 5sin $\omega t$

$5=\frac{100}{R_y}\Rightarrow R_y=\frac{100}{5}=20\Omega$

When x and y both are connected in series :-

v = 100sin $\omega t$

tan = 1 = 45°

R₀ = $\sqrt[]{R_x^2+R_y^2}=20\sqrt[]{2}\Omega$

$\therefore \stackrel{o}{{\mathcal{l}}_0}=\frac{v_0}{R_0}=\frac{100}{20\sqrt[]{2}}=\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$\sqrt[]{2}$}\right.A.$

$\therefore {\mathcal{l}}_{ms}=\frac{{\mathcal{l}}_0}{\sqrt[]{2}}$

$=\frac{5}{\sqrt[]{2}\cdot \sqrt[]{2}}$

$=\frac{5}{2}A=\frac{5}{2}A$

Top recruiters at Radha Govind University include Amazon, Reliance, Flipkart, Patanjali, TATA Motors, and HDFC Bank. Though this data represents multiple departments, BCom students have also benefitted from these placement drives, making it a promising opportunity for Science graduates at the university.

Radha Govind University hasn't released an official placement report for its BCom programme. However, student reviews on Shiksha suggest a placement rate of around 70%–80%. While exact BCom-specific figures aren't available, many students reportedly secure jobs through campus placements and tie-ups with reputed companies.

$\left(\overrightarrow{a}\times \overrightarrow{b}\right)\times \widehat{i}=\left(\overrightarrow{a}.\widehat{i}\right)\overrightarrow{b}-\left(\overrightarrow{b}.\widehat{i}\right)\overrightarrow{a}$

$\left(\left(\overrightarrow{a}\times \overrightarrow{b}\right)\times \widehat{i}\right).\widehat{k}=\left(\overrightarrow{a}.\widehat{i}\right)\left(\overrightarrow{b}.\widehat{k}\right)-\left(\overrightarrow{b}.\widehat{i}\right)\left(\overrightarrow{a}.\widehat{k}\right)$

BHU PhD admission process is based on the performance of a candidate in an entrance exam conducted by the University (RET). For seeking admission, eligible candidates need to fill PhD application form and submit it along with mandatory enclosures to the university's admission cell.

Yes, Chandragupt Institute of Management is good for PGDM placements 2025. The institute has released the overall placement 2025 report byt branch-wise packages is yet to out. Refer to the table below for overall details of CIMP PGDM placements 2025.

Time to reach at max height t = $\frac{u}{g}no.$ of balls thrown in 1 sec = n.

So, time taken by each ball to reach maxm height, = $\frac{1}{n}sec$

i.e. $\frac{u}{g}=\frac{1}{n}\Rightarrow u=\frac{g}{n}$ So, hmax = $\frac{u^2}{2g}$

= $\frac{g^2}{2g{n}^2}$

$=\frac{g}{2n^2}$

Yes, Chandragupt Institute of Management is known for its excellent placements. The table given below lists details concerning placements packages and companies for PGDM course during CIMP placements 2025. 

BCom candidates of Radha Govind University must upload scanned copies of Class 10 and Class 12 marksheets, a recent passport-sized photograph, and a valid government-issued photo ID (like Aadhaar or PAN). These documents are mandatory during the online application process for verification and eligibility confirmation. Ensure clarity and accuracy before uploading to avoid rejection.

Once a candidate is shortlisted, they receive an official admission offer. The final step is to pay the required course fee to confirm the seat. The BCom programme fee at Radha Govind University is INR 24,000. Timely fee submission is crucial, as it secures admission and completes the enrollment process.

Admission to the BCom programme at Radha Govind University is strictly based on merit. Candidates are shortlisted according to their performance in Class 12 board examinations. There is no entrance exam required. Final selection depends on academic scores, seat availability, and fulfillment of all eligibility criteria as per university admission policies.

F_x-y = $\frac{{\mu }_0{i}_1{i}_2}{2\pi r}\times \left(.5\right)$

$=\frac{2\times 10^{-7}\times 6\times 0.5}{0.05}$

$=\frac{6}{5}\times 10^{-5}N=1.2\times 10^{-5}$

Force on Y = 1.2 × 105N towards ‘x’