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From  $\Delta APQ$ $$

$$ $\frac{x+15}{y}=tan75°$  …. (i)

From $\Delta RQA$ $$

$\frac{}{}$  $\frac{15}{y}=tan60°$ …… (ii)

From (i) and (ii)

$=5\left(2\sqrt[]{3}+3\right)m$

we know,   $C=\frac{1}{\sqrt[]{{\mu }_0\in o}}=3\times 10^8,Given,{\in }_r=1$

$v=\frac{1}{\sqrt[]{{\mu }_0{\in }_r{\in }_o{\mu }_r}}=2\times 10^8$            

$\Rightarrow \frac{3\times 10^8}{2\times 10^8}=\sqrt[]{{\in }_r{\mu }_r}$               

$={\left(1.5\right)}^2={\in }_r{\mu }_r$              

${\mu }_r=2.25$               

The duration of BA B.Ed. at RIE Bhubaneswar is of four years. Admissions to this course are entrance-based. Candidates must appear for the CEE exam to take admission in the same. They must also ensure fulfilling the eligibility criteria before applying for admission. 

The MBA HHM is the best branch when it comes to placements. The key highlights of Symbiosis Institute of Health Sciences placements 2022-2024 are tabulated below:

Number of solution of the equation |cos x| = sin x for $x\in \left[-4\pi ,4\pi \right]$ $$ will be equal to 4 times the number of solutions of the same equation for $x\in \left[0,2\pi \right]$ $$

Graphs of y = |cos x| and y = sin x are as shown below.

Hence, two solutions of given equation in [0, 2]

$$ $\Rightarrow$  total of 8 solutions in [4, 4]

The SIHS Pune has had a good record for placements. The key highlights of Symbiosis Institute of Health Sciences placements 2022-2024 are tabulated below:

RIE Bhubaneswar offers the BA B.Ed course is generally considered a good option. Candidates must consider factors like infrastructure, faculty experience, hostel and mess facilities, curriculum, etc. while taking admission. They can apply online or offline for admission at RIE Bhubaneswar.

Yes, a BTech student is eligible for the TS EdCET exam. The degree must be from a recognised university with at least 50% marks. They can choose only some methodologies, like Maths.

IIM Mumbai offers financial assistance in the form of financial assistance to PhD scholarships. During the first and second years of the PhD, students get INR 37,000 per month. Additionally, during the third, fourth and fifth years of the programme students receive INR 42,000 per month as a stipend. 

V = 210 sin 3000 t

$\omega$ = 3000

$X_L=\omega L=30$                

$X_C=\frac{1}{\omega c}=\frac{40}{3}$                

$tan?=\frac{V_L-V_C}{V_R}=\frac{X_L-X_C}{R}$                

$\begin{array}{l}tan?=0.17\\ ?=ta{n}^{-1}\left(0.17\right)\end{array}$                

For $x^2+\alpha x=\beta >0\forall x\in R$  to hold, we should have   ${\alpha }^2-4\beta <0$

If $\alpha =1,\beta$  can be 1, 2, 3, 4, 5, 6 i.e., 6 choices

If a  = 4, b can be 5 or 6 i.e., 2 choices

hence total favourable outcomes

= 6 + 5 + 4 + 2 + 0 + 0 = 17

Required probability =  $\frac{17}{36}$

SSC Stenographer exam include subjects such as General Intelligence & Reasoning, General Awareness, English Language & Comprehension. Candidates must understand the exam pattern, cover important topics and use trusted books as given below:

• A Modern Approach to Verbal & Non Verbal Reasoning (R.S. Aggarwal)

• Objective General English (S.P. Bakshi / Wren & Martin)

• Lucent's General Knowledge, Manorama Year Book for GK

Out of 153 total seats at OUAT BSc, 100 are allotted for BSc (Hons.) Agriculture, while 21 seats fall under a separate Agriculture category. Other specialisations include 13 seats for Community Science, 12 for Horticulture, and 7 for Forestry. The division is subject to university norms and reservation rules.

OUAT offers a total of 153 seats across its BSc (Hons) programmes. These are distributed among various specialisations such as Agriculture, Horticulture, Forestry, and Community Science. The number of seats may vary based on category and reservation guidelines issued by the university.

If n is number of trials, p is probability of success and q is probability of unsuccess then,

Mean = np and variance = npq.

Here np + npq = 24         …. (i)

np. npq = 128                   …. (ii)

and q = 1 – p                    …… (iii)

From eq. (i), (ii) and (iii) :

$=\left(32+\frac{32*31}{2}\right).\frac{1}{2^{32}}$      

$=\frac{33}{2^{28}}$

The eligibility criteria for B.Ed at RIE Bhubaneswar requires the candidates to pass Bachelor's Degree and/or the Master's degree with at least 50% aggregate in Sciences/Social Sciences/Humanities, Bachelor's in Engineering or Technology with specialization
in Science and Mathematics with 55% marks or in any other qualification (50% for reserved category).

  $B=\eta {\mu }_{0}l$

 if l ->2l

$\eta \to \raisebox{1ex}{$n$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$                

$B^1=\frac{n}{2}{\mu }_{0}2l$

$B^1=B$                

The TS EdCET 2025 qualifying marks for candidates other than SC/ST are 25% of the aggregate marks (38 out of 150). There are no minimum qualifying marks for SC/ST candidates. The cutoff marks will be released along with the results, and the counseling process will be based on these marks and ranks.