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Let initial moles of reactant taken = n. Total moles obtained for benzene sulphonic acid = 0.6 n (with % yield = 60%)

Moles of benzene sulphonic acid before reaction II = 0.6n

Moles obtained for phenol (with % yield 50%) = 0.6 × 0.5 n = 0.3 n

So, overall % age yield of complete

reaction = $\frac{0.3n}{n}\times 100=30\mathrm{\%}$  

$\mathrm{\%}Opticalpurity=\frac{Observedrotationofmixture\times 100}{rotationofpureenautiomer}$

$=\frac{+12.6}{+30}\times 100=42\mathrm{\%}$

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  $2KMn{O}_4+5H_2{\stackrel{+3}{C}}_2{O}_4+3H_{2}S{O}_4\left(dil\right)\to K_{2}S{O}_4+2MnS{O}_4+10C{\stackrel{+4}{O}}_2+8H_{2}O$

Oxidation state of carbon changes from +3 to +4

$\therefore$ change in O. S is 1

Yes, a candidate is eligible for admission in RIE Bhubaneswar with 70% in Class 12. The minimum aggregate required for all the courses is 50-55%. There is a 5% relaxation for reserved category candidates. Since 70% is a good score, thye can get admission in their preferred course at the institue. However, they must ensure fulfilling the eligibility criteria before applying or admission in the institute. 

Complex is   $\left[Co{\left(N{H}_3\right)}_{4}C{l}_2\right]Cl$

Primary valency = No. of ionisable species = 1

Candidates are selected for admision in B.Ed course at RIE Bhubaneswar on the basis of the CEE exam. This is known as the Common Entrance Exam and candidates must appear for this and achieve a valid aggregate in the same. They must register for this exam online on the official website of the institute. 

Amrapali University offers a BCom programme that runs for a duration ranging from three to four years. The total fees to pursue this programme amounts to INR 4.59 lakh. This fee comprises two components: tuition fees and hostel fees. Moreover, students must note that they may have to pay additional fee components. To know more, students can check out the below table:

Note: The above-mentioned fee is as per the official sources. However, it is indicative and subject to change.

Solubility of CaF₂ = S mol/L

$S=\frac{2.34\times 10^{-3}}{0.1\times 78}=\frac{2.34}{78}\times 10^{-2}=3\times 10^{-4}mol/L$          

$K_{sp}\left(Ca{F}_2\right)=4S^3=4{\left(3\times 10^{-4}\right)}^3=108\times 10^{-12}$        

= 0.0108 × 10^-8 (mol/L)³

The eligibility criteria to take admission in MA course at RIE Bhubaneswar requires the candidates to pass graduation in any sttream with a minimum of 50% aggregate. There is a 5% relaxation given for reserved category in the same, i.e., 45%. Candidates must ensure fulfilling this eligibility criteia before applying for admission in the MA course at RIE Bhubaneswar.

  $C{N}^{-},N{O}^{+}and{O}_2^{2+}$ have bond order = 3

$C_{P,m}=C_{v,m}+R$

$C_{v,m}=20.785-8.314=12.471J{K}^{-1}mo{l}^{-1}$

$n=\frac{5000}{12.471\times 200}=\frac{25}{12.471}\approx 2$

$K{O}_2,N{O}_2,Cl{O}_2,NO$ are paramagnetic.

Some of the notable PSUs in India that accept GATE scores are as follows -

• NTPC 
• SBI
• ONGC
• GRID-INDIA
• NPCIL
• GAIL, etc. 

East Point Group of Institutions applications are currently open for 2026 session. The institute has not released any application deadline yet. Candidates are advised to apply as soon as possible to avoid missing out the chance. East Point Group of Institutions releases application forms online on the official EPGI website.

Yes, the BTech course at Odisha University of Agriculture and Technology includes a strong emphasis on practical learning. The programme is designed to offer students real-world exposure alongside academic knowledge in Agricultural Engineering.

For BTech admission at OUAT, the UG counseling is scheduled from August 4 to 13, 2025. Campus reporting for undergraduate programmes through multiple rounds is expected to take place throughout September 2025. These dates are tentative, so candidates are advised to regularly visit the official OUAT website for the latest updates and detailed admission timelines.