Ask & Answer: India's Largest Education Community

To get admissions into K J Somaiya Institute of Technology BTech courses, candidates first need to register themselves on the official website of K J Somaiya Institute of Technology. Then, the candidates need to apply for the entrance exams available to them and appear for the same. 

If the candidate scores an appropriate rank, they will sent an offer letter with a SVV ID which can be used to access the admission form. Filling the admission form and paying the fees will complete the K J Somaiya Institute of Technology BTech admission process.

No, Georgetown University is not ranked among the top 20 universities in the world. Georgetown University is one of the most prestigious universities in the USA for to pursue International Business. The university is constantly ranked among the top universities in the world. According to Shiksha Popularity Rankings, Georgetown University has ranked at #277 in world and #56 in USA. Furthermore, check the table listed below for Georgetown University rankings by various ranking agencies worldwide:

Georgetown University and Vanderbilt University are some of the top ranked universities all over the world. According to Shiksha Popularity Rankings, Georgetown University has an overall ranking of #277 in world. On the other hand, Vanderbilt University has an overall ranking of #151 in world. In terms of Shiksha Popularity rankings, Vanderbilt University has an upper hand. Furthermore, check the table listed below for Georgetown and Vanderbilt University ranking by various ranking bodies worldwide:

The K J Somaiya Institute of Technology BTech course fees typically includes multiple fee components such as University enrollment fees, E-Charges, student insurance, Amartya Insurance, etc. The charges for each of these fee components is currently unknown. The total fees for K J Somaiya Institute of Technology BTech course ranges between INR 3.8 Lacs - INR 7.21 lakh.

The top three majors at the University of Houston-Clear Lake at UG and PG levels can be checked out from the table given below, along with the number of degree recipients for each major:

The 2025-26 costs of attendance for UHCL international students is as follows:

 1 USD = INR 86.89

The current tuition fee structure for K J Somaiya Institute of Technology BTech courses is unknown. The fee structure is usually designed on a per semester basis where the total tuition fee is divided into instalments equal to the number of semesters in the course. At K J Somaiya Institute of Technology, BTech courses have a duration of 4 years or 8 semesters. 

${=}^{10}{C}_r.2^{10-r}.3^r.x^{30-3r-r}$  

  $For{x}^{30-4r}\to x^{\left(even\right)}$              

r = 0, 1, 2, 3, 4, 5, 6, 7

$r\in \left\{0,1,2,......,10\right\}$          

Sum of all such coefficient

While the subject and predicate are important to sentence structure in both spoken and written English, they may be less formally emphasized in spoken language, especially in casual conversation. However, in written English, the subject and predicate are more clearly defined and often form the foundation of clear and concise writing.

Here are some books to study Subject and Predicate in detail:

  ${\displaystyle \underset{3}{\overset{b}{\int }}\frac{1}{3}\left(\frac{1}{x^2-4}+\frac{1}{x^2-1}\right)}dx$

$=\frac{1}{3}{\left[\frac{1}{4}\mathcal{l}n\frac{x-2}{x+2}-\frac{1}{2}\mathcal{l}n\frac{x-1}{x+1}\right]}_3^6$

$=\mathcal{l}n{\left(\frac{49}{40}\right)}^{\frac{1}{12}}$

$\frac{5\left(b-2\right)}{b+2}/\frac{4{\left(b-1\right)}^2}{{\left(b+1\right)}^2}=\frac{49}{40}$

$\frac{4b}{2\left(b^2+1\right)}=\frac{-b+198}{99b-2}$

->b³ – 3b – 198 = 0

b = 6

The BTech course with the least competition for admissions was B.Tech in Electronics and Telecommunication Engineering at K J Somaiya Institute of Technology. In JEE Mains cutoff, the closing rank for B.Tech in Electronics and Telecommunication Engineering was 47,344 in the last round. This closing rank is noticably lower than the other BTech courses offered by K J Somaiya Institute of Technology.

Here are some examples:

President Obama was a successful leader.

Subject: President Obama

Predicate: was a successful leader

The dog is sitting on the table.

Simple subject: Dog

Simple predicate: sitting on table  

Georgetown Uni is among the top ranked universities worldwide. Georgetown offers more than 210 degree programs at undergraduate and postgraduate levels for its international students. Also, Georgetown University is ranked by top ranking authorities worldwide and nationally. 

  $f\left(x\right)=\left[2x^2+1\right]$

  $g\left(x\right)=\{\begin{array}{l}2x-3,x<0\\ 2x+3,x\ge 0\end{array}$

  $f\left(g\left(x\right)\right)=\left[2{\left(g\left(x\right)\right)}^2\right]+1$              

 for 0 < x < 1

-3 < 2x – 3 < -1

2 < 2 (2x – 3)² < 18

31 + 15 = 46

Subject and Predicate are crucial parts of a sentence, that bring clarity and meaning in communication. The subject identifies who or what the sentence is about, while the predicate explains what the subject does or is. Thus, understanding about these two is important for effective writing, and clear comprehension.

$A=\left[\begin{array}{cc}\hfill 2\hfill & \hfill -2\hfill \\ \hfill 1\hfill & \hfill -1\hfill \end{array}\right]$ $B^2=\left[\begin{array}{cc}\hfill -1\hfill & \hfill 2\hfill \\ \hfill -1\hfill & \hfill 2\hfill \end{array}\right]\left[\begin{array}{cc}\hfill -1\hfill & \hfill 2\hfill \\ \hfill -1\hfill & \hfill 2\hfill \end{array}\right]$                  

$B=\left[\begin{array}{cc}\hfill -1\hfill & \hfill 2\hfill \\ \hfill -1\hfill & \hfill 2\hfill \end{array}\right]$ $=\left[\begin{array}{cc}\hfill -1\hfill & \hfill 2\hfill \\ \hfill -1\hfill & \hfill 2\hfill \end{array}\right]=B$

$A^2=\left[\begin{array}{cc}\hfill 2\hfill & \hfill -2\hfill \\ \hfill 1\hfill & \hfill -1\hfill \end{array}\right]\left[\begin{array}{cc}\hfill 2\hfill & \hfill -2\hfill \\ \hfill 1\hfill & \hfill -1\hfill \end{array}\right]$ $\Rightarrow .....B^3=B^2=B\Rightarrow B^n=B$

$=\left[\begin{array}{cc}\hfill 2\hfill & \hfill -2\hfill \\ \hfill 1\hfill & \hfill -1\hfill \end{array}\right]=A$

$\Rightarrow ...=A^3=A^2=A\Rightarrow A^n=A$

$n{A}^n+m{B}^m=l\Rightarrow nA+mB=l$

$\left[\begin{array}{cc}\hfill 2n\hfill & \hfill -2n\hfill \\ \hfill n\hfill & \hfill -n\hfill \end{array}\right]+\left[\begin{array}{cc}\hfill -m\hfill & \hfill 2m\hfill \\ \hfill -m\hfill & \hfill 2m\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right]$

$\Rightarrow 2n-m=1$  n – m = 0            ->n = m = 1

-2n + 2m = 0     -n + 2m = 1

  $\frac{x^2}{4}+\frac{y^2}{2}=1$              

lim PQ is y = x + 1

$\frac{x^2}{4}+\frac{{\left(x+1\right)}^2}{2}=1$               

$\Rightarrow {\left(x_1-x_2\right)}^2={\left(-\frac{4}{3}\right)}^2-4\left(-\frac{2}{3}\right)=\frac{16}{9}+\frac{8}{3}=\frac{40}{9}$               

y = x + 1

$y_1-y_2=x_1-x_2$

$P{Q}^2=\frac{80}{9}\Rightarrow \frac{PQ}{2}=r=\frac{\sqrt[]{80}}{6}$

$r=\frac{4\sqrt[]{5}}{6}\Rightarrow {\left(3r\right)}^2={\left(2\sqrt[]{5}\right)}^2=20$               

  $ta{n}^{-1}\left(\frac{\frac{1}{\sqrt[]{2}-1}}{\frac{1}{\sqrt[]{2}}}\right)$

$=ta{n}^{-1}\left(1-\sqrt[]{2}\right)$

$=ta{n}^{-1}\left(\sqrt[]{2}-1\right)$

$=-\theta$

$tan\theta =\sqrt[]{2}-1$

$tan2\theta =\frac{2\left(\sqrt[]{2}-1\right)}{1-{\left(\sqrt[]{2}-1\right)}^2}$

$=\frac{2\left(\sqrt[]{2}-1\right)}{2\left(\sqrt[]{2}-1\right)}$

tan 2 θ = 1

$\theta =\frac{\pi }{8}$