Wavelength of light used in an optical are lambdas 4000angustrom and 5000 A. What will be the ratio of their respective resolving power?
a. 26:26 b. 4:5 c. 9:1 d. 5:4
-
1 Answer
-
As I remember resolving power of an optical instrument is inversely proportional to the wavelength of light:
So the ratio of their resolving powers:
Ratio of resolving powers = 5 : 4 (or 1.25)
Similar Questions for you
Not really. The electric dipole moment vector directs or points from the negative charge to the positive charge. But the electric field lines that a dipole creates will point away from the positive and move to the negative charge.
Yes, the cube, which is a closed surface containing only one electric dipole will make electric flux zero. This follows Gauss's Law when the total charge inside it is zero. The field lines entering the surface will exit, and that would result in zero net flux.
The magnitude of each charge and the distance that separates them.
Gauss Law is only concerned with the total enclosed charge that finally tells us the total flux. The charges outside may change field patterns. They not affect the total flux. It's actually incorrect to assume the field due to the external charges should also affect the flux through the Gaussian surface.
Gauss Law does not directly give the electric field in all cases. It can only be used in calculations for symmetrical surfaces: spherical, cylindrical, or planar.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 679k Reviews
- 1800k Answers