Wavelength of light used in an optical are lambdas 4000angustrom and 5000 A. What will be the ratio of their respective resolving power?

a. 26:26 b. 4:5 c. 9:1 d. 5:4

0 6 Views | Posted 3 weeks ago
Asked by Vidya Khating

  • 1 Answer

  • Y

    Answered by

    YOGESH K MISHRA

    3 weeks ago

    As I remember resolving power of an optical instrument is inversely proportional to the wavelength of light:

    R1wR \propto \frac {1} {\lambda}

    So the ratio of their resolving powers:

    R1R2=w2w1=50004000=54=1.25\frac {R_1} {R_2} = \frac {\lambda_2} {\lambda_1} = \frac {5000} {4000} = \frac {5} {4} = 1.25

    Ratio of resolving powers = 5 : 4 (or 1.25)

     

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