Wavelength of light used in an optical are lambdas 4000angustrom and 5000 A. What will be the ratio of their respective resolving power?

<p data-start="0" data-end="98">As I remember resolving power of an optical instrument is inversely proportional to the wavelength of light:</p><p><math ><semantics><mrow><mi>R</mi><mo>∝</mo><mfrac><mn>1</mn><mi>w</mi></mfrac></mrow>&lt;annotation encoding="application/x-tex"&gt;R \propto \frac {1} {\lambda}</annotation></semantics></math></p><p data-start="209" data-end="248">So the ratio of their resolving powers:</p><p><math ><semantics><mrow><mfrac><msub><mi>R</mi><mn>1</mn></msub><msub><mi>R</mi><mn>2</mn></msub></mfrac><mo>=</mo><mfrac><msub><mi>w2</mi></msub><msub><mi>w1</mi></msub></mfrac><mo>=</mo><mfrac><mn>5000</mn><mn>4000</mn></mfrac><mo>=</mo><mfrac><mn>5</mn><mn>4</mn></mfrac><mo>=</mo><mn>1.25</mn></mrow>&lt;annotation encoding="application/x-tex"&gt;\frac {R_1} {R_2} = \frac {\lambda_2} {\lambda_1} = \frac {5000} {4000} = \frac {5} {4} = 1.25</annotation></semantics></math></p><p data-start="389" data-end="442" data-is-last-node="" data-is-only-node="">Ratio of resolving powers = 5 : 4 (or 1.25)</p><p>&nbsp;</p>

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