What are the cutoff marks for Gandhi Engineering College?
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2 Answers
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The basics requirement of GCE (Gandhi college of engineering) in Bhubaneswar is that student has 45% in 10+2 with chemistry, physics, and mathematics. And the student should also score good marks in JEE exam and the OJEE . According to the previous cutoff of GCE in general category is 420 in JEE exam and approximately 460 in OJEE exam.
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To be eligible for admission to Gandhi Engineering College (GEC) in Bhubaneswar, students must score at least 45% in class 12 and have a good rank in the OJEE or JEE main exam.Here are some other cutoff marks for GEC:
- OJEE 2022: The overall cutoff for the general category is 463–22404 rank.
- JEE-Main 2022: The overall cutoff is 483548–844869 rank.
- BTech: Students must have a bachelor's degree with a minimum of 50% marks and appear for the OJEE, CAT, MAT, XAT, or ATMA exams.
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