What are the cutoff marks required for B.Tech at Techno India University?
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2 Answers
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The cutoff marks for B.Tech at Techno India University (TIU) depend on the entrance exam score and the branch of engineering chosen by the candidate. According to the web search results, TIU accepts scores of WBJEE, JEE Main, and JELET for B.Tech admission. The cutoff ranks for different branches of engineering for the general category in 2023 are as follows:
- Computer Science Engineering: 61789 (WBJEE), 89555 (JEE Main)
- Artificial Intelligence and Machine Learning: 66908 (WBJEE), 99986 (JEE Main)
- Electronics & Communication Engineering: 106571 (WBJEE), 146428 (JEE Main)
- Biotechnology: 123771 (WBJEE), 295479 (JEE Main)
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In order to be admitted to B.Tech programs, applicants must have completed PCM in their 10+2 exam or an equivalent exam.
Candidates in the general category must have earned at least 60% of their points in PCM subjects overall. The minimum amount needed in PCM for SC/ST categories that are reserved is 50%.The WBJEE (West Bengal Joint Entrance Examination) score determines admission. The University of Techno India accepts WBJEE scores.
CS: Under 2000; Electrical/Electronics: Under 5000
Mechanical: Less than 8,000
Civil - Less than 12,000
These rankings are representative of students in the general category.To sum up, in order to be elig
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