What are the cutoff marks required for B.Tech?
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2 Answers
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Eligibility Criteria:
Candidates must pass their 10+2 or equivalent exam with a minimum of 50 percent marks from a recognised institution.The JEE Main 2023 cutoff has been released for different categories such as for General Category is 90 percentile while the IIT JEE cut off 2023 for OBC-NCL is 73.611, EWS is 75.622, SC is 51.977. The cut-off of JEE Main is released in two forms i.e., qualifying cut-off and admission cut-off.
General Category candidates need to score a minimum of 95 percentile score to get NITs. For reserved category candidates, the 80 percentile score is enough to get NITs.
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Cutoff will change category wise. General category candidates should have scored minimum 50% marks in 10+2 examination. For reserved category candidates, the minimum marks to be secured is 45%
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