What are the desired cutoff marks for B.Tech at Mahindra University?
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2 Answers
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To be eligible to apply directly, you will need a cutoff aggregate marks of 45% in your class 12.
Mahindra University accepts JEE and SAT exam marks. For SAT, the minimum score in one of the tests is 1800 and in one subject, you will need a minimum of 800.
For JEE mains, the minimum acceptable marks is 130, the cut-off ranks are not specified.
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The cutoff marks required for B.Tech at Mahindra University depend on the mode of admission. For admission through JEE (MAIN) 2024 and being eligible to write JEE Advanced 2024, or having a top All India Rank in JEE (MAIN) 2024, the exact cutoff rank would be displayed upon the announcement of results. For admission through a valid SAT Subject test score, a minimum score of 1800 is required, or a valid SAT Test score with a minimum of 800, or a valid ACT score with a minimum composite score of 18. Score also vary depending upon what stream you are chosing for example For the B.Tech (Computational Biology) programme valid SAT Test score
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