What is the average package received during IIT Roorkee CSE placements?
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2 Answers
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The average package of B.Tech CSE students in IIT Roorkee in the 2024 placement season was roughly 34.07LPA, and the median was also roughly 34 LPA
branch-wise placement summary for IIT? Roorkee's 2024 B.Tech (and related programs), including average and median packages:
Branch / Course Average Package ( LPA) Median Package ( LPA) Pre-placement Offers (PPOs) Computer Science & Engineering (CSE) 34.07 34.00 52 Electronics & Communication (ECE) 23.52 21.50 36 Electrical Engineering (EE) 22.10 19.48 41 Chemical Engineering 19.43 16.50 13 Mechanical Engineering 19.56 16.58 23 Civil Engineering 15.10 13.00 10 Polymer Engineering 12.70 14.00 — Metallurgical Engineering 15.45 14.10 8 Engineering Physics 15.53 15.50 1 Production & Industrial Engineering 16.48 15.46 4 Biotechnology 17.84 16.00 1 Geological Technology 18.50 16.00 4 Geophysical Technology 21.73 19.81 7 Overall B.Tech Avg (all branches) ~20.00 — — M.Tech 13.48 12.00 — Architecture 9.70 7.50 — Integrated MSc Physics 5.06 4.80 — MSc Chemistry 12.25 10.00 — IMSc Applied Mathematics 36.00 34.62 11 MSc Physics 13.64 12.00 — MSc Economics 14.00 14.00 — - setting & Details
- IIT Roorkee has one of the best CSE placements in India, and the average CTC is equal to that of top IITs such as Guwahati and Hyderabad
- Microsoft, Google, Amazon, Goldman Sachs and other top global & Indian companies recruit highly from campus.
Insights
CSE is the highest in average (~Rs 34 LPA).Other mainstream branches (ECE, EE) are also doin
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The average package received during IIT Roorkee CSE placements 2025 stood at INR 34.05 LPA. For other top branch such as ECE and EE, the average package received in 2025 was INR 30.81 LPA and INR 28.36 LPA.
Similar Questions for you
Candidates who have passed a master's degree are eligible to apply for PhD programme at DoMS IIT Roorkee. Besides, aspirants must also pass any of the accepted entrance exams for admission. The institute considers scores in GATE, CAT, UGC-JRF, UGC-NET or CSIR JRF for admission. Selected candidates have to further the pass the personal interview round for final admission.
The IIT Roorkee UCEED cutoff 2025 was released for different categories of students belonging to the All India quota. The institute accepts the UCEED entrance exam, followed by counselling rounds for B.Des admission. For the General category students belonging to the AI quota, the UCEED last round closing rank stood at 111. Please note that the cutoff ranks vary across different rounds and categories. The category-wise cutoff details for the last round are tabulated below:
Category | UCEED Cutoff 2025 (Last round closing rank) |
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General | 111 |
OBC | 56 |
SC | 33 |
ST | 12 |
EWS | 18 |
No, if you belong to the OBC AI quota and are seeking admission to the IIT Roorkee B.Des course, 75 is not a good UCEED rank for admission. In 2025, the IIT Roorkee UCEED cutoff ranged between 51 and 56 for the students belonging to the OBC category under the AI quota. So, the target cutoff rank should be below 50 to secure a seat at IIT Roorkee. However, please note that final admission also depends on other factors, such as availability of seats, reservation criteria, etc.
IIT Roorkee UCEED cutoff 2025 concluded with the release of the Round 5 cutoff list. If you belong to the General AI quota, the last round closing rank for B.Des admission was 111. During Round 1 admission, the closing rank stood at 91 for the same category and quota. So, candidates seeking admission to the B.Des programme at IIT Roorkee must target to secure a cutoff rank of up to 111 or below. Please note that the cutoff ranks vary for different rounds and categories.
If you belong to the SC category under the AII India quota, the minimum JEE Advanced rank required for admission was 129 during Round 4 cutoff list. Please note that the cutoff ranks vary for different courses, specialisations and rounds. The maximum rank required during Round 4 admission was 2556 for the BTech course across multiple specialisations. Candidates can refer to the table below to view the IIT Roorkee JEE Advanced cutoff 2025 for Round 4:
Course | JEE Advanced Cutoff 2025 (SC AI Quota) |
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B.Tech. in Computer Science and Engineering | 129 |
B.Tech. in Data Science and Artificial Intelligence | 213 |
B.Tech. in Electronics and Communication Engineering | 394 |
B.Sc. + M.Sc. in Mathematics and Computing | 569 |
B.Tech. in Electrical Engineering | 572 |
B.Tech. in Mechanical Engineering | 1039 |
B.Tech. in Chemical Engineering | 1333 |
B.Tech. in Energy Engineering | 1470 |
B.Tech. in Engineering Physics | 1540 |
B.Tech. in Civil Engineering | 1655 |
B.Tech. in Production and Industrial Engineering | 1717 |
B.Tech. in Metallurgical and Materials Engineering | 2026 |
Integrated B.Sc. + M.Sc. in Economics | 2176 |
B.Tech. Biosciences and Bioengineering | 2210 |
Integrated B.Sc. + M.Sc. in Physics | 2240 |
B.Sc. + M.Sc. in Chemical Sciences | 2318 |
Integrated M.Tech. in Geophysical Technology | 2486 |
Integrated M.Tech. in Geological Technology | 2556 |
Bachelor of Architecture (B.Arch.) | 3181 |
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