What is the cutoff mark for CIEM - Calcutta Institute Of Engineering & Management?

0 4 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 2 Answers

  • A

    Answered by

    Anurag tiwari | Contributor-Level 10

    3 days ago

    The cutoff marks for the Calcutta Institute of Engineering and Management (CIEM) for 2024 are as follows:

    B.Tech Computer Science Engineering: Round 1: 20,397, Round 2: 73,499 

    B.Tech Information Technology: Round 1: 60,285, Round 2: 1,02,182 

    B.Tech Electronics & Communication Engineering: Round 1: 91,921 

    B.Tech Civil Engineering: R1 (Closing Rank): 110,942 

    B.Tech Electrical Engineering: R1 (Closing Rank): 97,333 

  • S

    Answered by

    Shiv Kumar | Contributor-Level 10

    a week ago

    The WBJEE cutoff for the Calcutta Institute of Engineering & Management (CIEM) for the year 2024 is as follows:

    • B.Tech Computer Science Engineering:
      • Round 1: 20,397
      • Round 2: 73,499
    • B.Tech Information Technology:
      • Round 1: 60,285
      • Round 2: 1,02,182
    • B.Tech Electronics & Communication Engineering:
      • Round 1: 91,921
      • Round 2: Data not available.

    These cutoff ranks represent the closing ranks for the respective rounds of the WBJEE (West Bengal Joint Entrance Examination) counseling process. If you're planning to apply, it would be best to monitor further announcements on the official WBJEE website or CIEM's admission portal.

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