What is the cutoff of IIT Roorkee for 2025 admission?
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1 Answer
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Through JEE Advanced ranks, candidates can secure admission to BTech courses. With regards to the admission, the IIT Roorkee cutoff 2025 has been released for the first round by the institute. The cutoff was released for different categories under the All India quota. For the General AI category candidates, the cutoff ranks varied between 535 and 16596, for different BTech/Integerated BTech/BSc/BArch courses. Among the OBC category candidates, the cutoff ranks varied between 244 and 6237. For the SC AI category candidates, the ranks varied between 121 and 3181. For more information on cutoff for IIT Roorke
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For the JEE advanced syllabus, please visit the official website JEE advanced.
You will get it there easily.
NIT Agartala cutoff 2025 has been released for the third round, based on JEE Advanced scores. The cutoff was released for different categories belonging to the All India and Home State quota. Among the General AI category candidates, the closing ranks in the third round varied between 20541 and 58197. Therefore, at 50,000 rank in JEE Advanced, student can get admission to the college.
Among the General Home State quota, the closing ranks in the third round varied between 70884 and 317100. Among the General Home State category candiates also, there is a chance of getting admission at 50,000 rank.
Yes, it is possible to get admission to MNIT Jaipur with a 30,000 rank in JEE Advanced. The closing ranks for MNIT Jaipur among the General AI category candidates varied between 612 and 35384. With this cutoff range, the General AI category candidates can easily get admission to the college.
For the General Home State quota candidates, the closing ranks in the third round varied between 1615 and 33621. Therefore, among the General Home State quota candidates also, there is a chance of gettting admisison at 30,000 rank in JEE Advanced.
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