What is the cutoff of IIT Roorkee for 2025 admission?
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1 Answer
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Through JEE Advanced ranks, candidates can secure admission to BTech courses. With regards to the admission, the IIT Roorkee cutoff 2025 has been released for the first round by the institute. The cutoff was released for different categories under the All India quota. For the General AI category candidates, the cutoff ranks varied between 535 and 16596, for different BTech/Integerated BTech/BSc/BArch courses. Among the OBC category candidates, the cutoff ranks varied between 244 and 6237. For the SC AI category candidates, the ranks varied between 121 and 3181. For more information on cutoff for IIT Roorke
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Similar Questions for you
To be eligible for JEE Advanced JoSAA counselling:
- Candidates should have JEE Advanced rank
- Candidates must have passed class 12 or equivalent exam
- Candidates should have studied Physics, Chemistry and Maths in class 12
- In class 12, canmdidates must have score 75% aggregate marks or must be in top 20 percentile scorers in class 12 of their respective school board.
No, your candidature will be rejected as you need to have minimum of 75% in class 12 to be eligible for admisison to the IITs, NIT, IIITs and GFTIs via the JoSAA counselling. Even if you pass JEE Advanced and JEE Main, of you do not have 75% minimum marks in class 12 boards you will no get admissions.
Devdutta Majhi was the female topper in JEE Advanced 2025. She has scored 312 marks out of 360 marks and got anm all India rank of 16.
In 2025, the number of male candidates who passed JEE Advanced were 44,974 and 9,404 females qualified.
1,87,223 candidates registered for JEE Advanced 2025 and 1,80,422 appeared in the exam. Of them, 54,378 passed the JEE Advanced exam in 2025.
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