what is the derivative of secxtanxdx

i cannot understand the concept properly

108 Views|Posted 2011-04-30 16:31:16

Asked by Pranav Deolasi

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Answered by

Manish Ramachandran | Contributor-Level 10

2011-04-30 16:42:26

Hi Pranav. secx(tanx + cosx) first simplify by distributing the secx secx(tanx + cosx) = secxtanx + secxcosx = secxtanx + 1 now, differentiate using the product rule on secxtanx d (secxtanx + 1) = [secxsecx + tanxsecxtanx] + 0 dx = secx[secx + tanx] ANSWER = secx[secx + (s