What is the eligibility criteria for M.Tech course at IIT Bhubaneswar?
IIT Bhubaneswar offers M.Tech course to students at the PG level. It is offered for 2 years in several specialisations. To be eligible for M.Tech at IIT Bhubaneswar, candidates must fulfil the eligibility criteria of the course. Candidates must have a BTech degree with at least 60% aggregate from a
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IIT Bhubaneswar offers entrance-based admission. For admission into flagship BTech courses, candidates need to clear JoSAA Counselling after clearing the JEE Main. For MSc, the selection criteria is based on IIT JAM exam along with CCMN Counselling. For admission in MTech, qualify GATE exam and
SC category students under the All India quota need a rank of at least 2336 to be considered eligible for a seat. Candidates can check the table below to know the Round 1 and Last Round closing ranks for the SC AI category.
| Course | Round 1 Cutoff 2026 | Last Round Cutoff 2026 |
|---|---|---|
| M.Sc. + Ph.D. in Chemistry | 2330 | 2336 |
| M.Sc. + Ph.D. in Mathematics | 1485 | 1485 |
| M.Sc. + Ph.D. in Physics | 2098 | 2229 |
| M.Sc. + Ph.D. in Geology | 444 | 463 |
| M.Sc. + Ph.D. in Atmosphere and Ocean Sciences | 1921 | 1921 |
EWS AI category students need a rank of at least 696 to be qualified for admission to the CSE course. Students can check the table below to know the round-wise IIT Bhubaneswar CSE cutoff 2026 for the EWS AI category.
| Round Number | IIT Bhubaneswar CSE cutoff 2026 (Closing Rank) |
|---|---|
| 1 | 643 |
| 2 | 643 |
| 3 | 643 |
| 4 | 643 |
| 5 | 696 |
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