What is the full procedure of JEE Mains and JEE Advanced paper course after 12th?
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3 Answers
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Yes, what Sohan Kumar said is right. I want to add some extra information.
JEE Mains has total of 90 questions each carrying 4 marks.
Total-360 marks
And there's negative marking also 1/4 negative for 1 wrong answer. -
JEE consists of 2 stages. One is Mains and other is Advance. Based on JEE Mains score, you can get admission in NITs and IIITs. You need to clear JEE Mains to appear for JEE Advance.
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JEE consists of 2 stages, one is Mains and other is Advance. Based on Mains marks you can get into NITs and IIITs and IITs are based on JEE advance. At first you need to appear for JEE Mains exam and score qualifying marks to get eligible for JEE Advance exam and you also need to have more than 75% in 12th boards. So, on the basis of your Advance score you can get into IITs.
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To get admission in the CSE branch at LPU based on your JEE Main result and 12th marks, follow these steps:
Eligibility Check: You need to have passed 10+2 with at least 60% aggregate marks in subjects like Physics, Mathematics, and English. Your 76% in 12th makes you eligible.
Apply Online: Visit website and register yourself.
Select JEE Main Mode: During application, choose “Admission through JEE (Main)” mode instead of LPUNEST if you want to use your JEE score. LPU accepts JEE scores for direct admission in B.Tech (including CSE).
Upload Documents: Submit your JEE scorecard and 12th mark sheet.
Scholarships: LPU provides scholarships
After attempting JEE mains, you can pursue the course what do you want and attending JEE counselling, you may get college based on your arrangement of order in counselling
I think there is something wrong with your, choice filling order you from obc ncl still you are not getting that NIT how is it possible with this rank . Participate in CSAB Special Round you will definitely get a very good seat.
IIIT Surat JEE Main cutoff 2025 has been released for the fourth round. As per the round 4 cutoff list, the closing ranks varied between 24479 and 33703 for candidates belonging to the General AI category. As per the cutoff range, 20,000 seemed to be a good rank for candidates belonging to the General AI category. With this rank, candidate can get admission to almost all the branches for which the cutoff has been released.
Tezpur University has released its B.Arch., BTech and BTech Integrated courses for the All India quotas. For All India, BTech cutoffs were released by the university. Considering the Tezpur University JEE Main cutoff 2025 for the Round 4 seat allotment results, yes, candidates scoring a rank of 50000 can get admission into the university. Candidates can even fetch BTech in CSE programme with this much of rank. The BTech in Computer Science Engineering cutoff stood at, 60587 for the General All India quota candidates.
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