what is the integration of logx

Let int( ) represent the integral function. Hence int(logxdx) = I (let) is to be calculated. Do it by integration by parts. Let logx = u, dx = dv v = int(dv) = x du = d(logx)/dx = 1/x Then int(udv) = uv - int(vdu) So int(logxdx) = xlogx - int(x.dx/x) Hence int(logxdx) = xlogx - int(dx) There