What is the JEE Mains cut off for BE in Computer Engineering in DY Patil College of Engineering, Akurdi?

To get admission at NIT Rourkela, General AI category students need to attain a rank of 85536 or below to be eligible, according to the last round NIT Rourkela JEE Main cutoff 2025. 

For the students who belong to the General HS category, the required rank needed for admission was at least 12735

NIT Rourkela JEE Mains cutoff 2025 concluded with the release of the final round cutoff. For the General AI category, the BTech CSE overall cutoff ranged from 3122 to 4245. On the other hand, for the General HS category, the overall cutoff varied between 7371 and 7853. Students should know that the

 IIITDM Kurnool BTech cutoff 2025 was released for various All India categories. For the BTech in Artificial Intelligence and Data Science course, admissions were closed at a rank of 46325 for the General AI category. In 2024, and 2023, the same course had a cutoff of 41928 and 44621, respectiv

IIIT Vadodara BTech cutoff 2025 was released for admission to the various BTech course specialisations.

For the BTech ECE course, the General AI category had an overall cutoff ranging from 31029 and 58622. For the OBC AI category, the same branch had a cutoff varying between 13598 and 75883

IIIT Vadodara BTech cutoff 2025 for the OBC AI category was declared for admission to various BTech specialisations. For this category, the overall cutoff ranged from 9585 to 97273. Students can refer to the table below to know the first and final round cutoff list for various branches.