What is the JEE Mains cutoff for admission in GIT Bhubaneshwar for BTech in CS machine learning?
Asked about Gurukula Institute of Technology (GIT Bhubaneswar) - B.Tech. in Computer Science and Engineering
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1 Answer
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The JEE Main cutoff for admission to B.Tech in Computer Science with Machine Learning specialization at Gurukula Institute of Technology (GIT), Bhubaneswar, for the general category shows an overall cutoff rank approximately around 1,508,189 for the JEE Main exam, based on recent data. This indicates the rank range within which students have been admitted through the JEE Main qualifying route.
Since Machine Learning is generally offered as a specialized branch under Computer Science Engineering, the cutoff tends to align closely with the general Computer Science branch cutoffs at similar institutes, which can vary by category, quo
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Courses | Eligibility |
---|---|
B.E. / B.Tech | Candidate must have passed 10+2 examination with Physics and Maths and any one subject out of 14 subjects (Physics/ Mathematics / Chemistry/ Computer Science/ Electronics/ Information Technology/ Biology/ Informatics Practices/ Biotechnology/Technical Vocational subject/ Agriculture/ Engineering Graphics/ Business Studies/ Entrepreneurship) and obtained at least 45% marks for general (40% marks for in case of candidates belonging to reserved category) in the above subjects taken together. |
M.E./M.Tech | Candidate must have completed Bachelor degree or equivalent in the relevant field of engineering and technology with above mentioned marks from any recognised University/Institute. 45% marks in case of candidates belonging to reserved category. |
MBA/PGDM | Candidate must have completed Bachelor degree of minimum 3 years duration with above mentioned marks from any recognised University/Institute. 45% marks in case of candidates belonging to reserved category. |
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