What is the KCET cut-off required for BE admission at MSRIT?
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1 Answer
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The KCET rank required to secure admission at MSRIT for BE varies from year to year. Further, it also varies depending on the candidates' reservation categories. Candidates need to clear the cut-off specified for their desired specialisations. The KCET cut-off for BE admission at MSRIT over the past three years for some specialisations is presented in the table below:
Course 2022 2023 2024 Electronics and Communication Engineering 3985 4094 4564 Electronics and Telecommunication Engineering 8977 7914 6551 Computer Science and Engineering 1125 1171 1626 Information Science and Engineering 2265 1995 3105 Artificial Intelligence and Data Science 3239 2860 4371
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No. The official authority does not release mock tests. Candidates need to refer to third party websites for the mock tests.
No. The JEE Mains emphasizes on deep knowledge and quote challenging with negative marking whereas KCET is moderately difficult which emphasizes on direct factual questions with no negative markings.
The exam tests knowledge of 11th and 12th syllabus so it is important to focus on 11th and 12th standard NCERT textbooks which gradually start by practicing previous years papers and appearing for mock examinations.
It is important to give mock tests for candidates appearing for KCET examination as it provides a holistic view and it provides a realistic exam experience also helping the candidates for analysing strengths and working on weaknesses.
The examination tests knowledge of 11th and 12th standard which includes subjects like physics, mathematics, chemistry and biology.
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