What is the latest cutoff information for M.Tech at Jaypee University of Engineering and Technology?

<p>When considering admission to the M.Tech programme at Jaypee University of Engineering and Technology (JUET), it's crucial to delve into the latest cutoff information to assess your eligibility for different branches. The JEE AIR 2023-Based Admission Cut-Off Rank and the 10+2 Merit-Based Admission Cut-Off Percentage provide valuable insights into the requirements for various specializations.</p><p>For instance, the JEE AIR 2023-Based Admission Cut-Off Rank for Computer Science and Engineering (CSE-62) stands at 65,607, indicating the rank you need to secure for admission. Similarly, the 10+2 Merit-Based Admission Cut-Off Percentage for CSE-62 is 95.33%, emphasizing the academic performance needed to meet eligibility criteria.</p><p>The data extends to other branches, such as Electronics and Communication Engineering (ECE-62) with a JEE AIR cutoff rank of 210,800 and a 10+2 merit-based cutoff percentage of 63.33%. This pattern repeats across various specializations, each with its specific cutoffs reflecting the competitive nature of admissions.</p><p>It's crucial to recognize that these cutoffs are dynamic and subject to change annually based on factors like the number of applicants and their overall performance. Regularly checking the official website of JUET for the most up-to-date information is advisable. Armed with this data, you can gauge your eligibility for different branches, aligning your academic and competitive performance with the specified cutoffs for a successful M.Tech admission journey.</p>

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<p>the JEE AIR 2023-Based Admission Cut-Off Rank and the 10+2 Merit-Based Admission Cut-Off Percentage for different branches at Jaypee Institute of Information Technology (JIIT) in Noida. These cutoffs play a crucial role in determining the eligibility of candidates for admission to various branches.</p><p>Here's a breakdown of the information you provided:</p><p><strong>JEE AIR 2023-Based Admission Cut-Off Rank:</strong></p><ol><li>CSE-62: 65,607</li><li>ECE-62: 210,800</li><li>IT-62: 79,219</li><li>BT-62: 115,686</li><li>INT-CSE: 136,648</li><li>INT-ECE: 208,680</li><li>EE-VLSI: 136,571</li><li>EC-ACT: 186,028</li><li>CSE-128: 128,693</li><li>ECE (CS)-128: 228,896</li></ol><p><strong>10+2 Merit-Based Admission Cut-Off Percentage:</strong></p><ol><li>CSE-62: 95.33%</li><li>ECE-62: 63.33%</li><li>IT-62: 94.33%</li><li>Biotech-62: 61.00%</li><li>INT-CSE: 90.67%</li><li>INT-ECE: 63.00%</li><li>INT-Biotech: 60.00%</li><li>EE-VLSI: 84.33%</li><li>EC-ACT: 81.00%</li><li>CSE-128: 90.67%</li><li>ECE-128: 67.00%</li><li>ECE (CS)-128: 63.00%</li></ol><p>These cutoffs represent the minimum ranks and percentages required for admission to different branches at JIIT Noida. Prospective students can use this information to gauge their eligibility for specific programs based on their JEE AIR and 10+2 merit. It is important for prospective students to note that these cutoffs are subject to change every year and may vary depending on the number of applicants and the overall performance of the candidates. Therefore, it is advisable to regularly check the official website of JIIT Noida for the most up-to-date information regarding admission cutoffs.&nbsp;</p>

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