What is the lowest rank to get into NIT Rourkela? I belong to the OBC category.
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1 Answer
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The closing rank was 1011 for admission to the CSE course for the OBC AI category. The cutoff rank varies for different courses, specialisations, rounds, and categories. The lower the cutoff rank, the higher the chances of getting admission to your desired course and college. Candidates can refer to the table below to view the NIT Rourkela JEE Main cutoff 2025 for Round 1 for OBC AI category students:
Course JEE Main Round 1 Cutoff 2025 Computer Science and Engineering (4 Years, Bachelor of Technology) 1011 Artificial Intelligence (4 Years, Bachelor of Technology) 1258 Electronics and Communication Engineering (4 Years, Bachelor of Technology) 1902 Electrical Engineering (4 Years, Bachelor of Technology) 3473 Electronics and Instrumentation Engineering (4 Years, Bachelor of Technology) 3641 Mechanical Engineering (4 Years, Bachelor of Technology) 4819 Chemical Engineering (5 Years, Bachelor and Master of Technology (Dual Degree)) 6210 Chemical Engineering (4 Years, Bachelor of Technology) 6340 Civil Engineering (4 Years, Bachelor of Technology) 7960 Industrial Design (4 Years, Bachelor of Technology) 8482 Metallurgical and Materials Engineering (4 Years, Bachelor of Technology) 8827 Mathematics (5 Years, Integrated Master of Science) 9201 Ceramic Engineering (4 Years, Bachelor of Technology) 9483 Biomedical Engineering (4 Years, Bachelor of Technology) 9577 Physics (5 Years, Integrated Master of Science) 9958 Mining Engineering (4 Years, Bachelor of Technology) 10124 Metallurgical and Materials Engineering (5 Years, Bachelor and Master of Technology (Dual Degree)) 10395 Biotechnology (4 Years, Bachelor of Technology) 10504 Ceramic Engineering and M.Tech Industrial Ceramic (5 Years, Bachelor and Master of Technology (Dual Degree)) 10733 Chemistry (5 Years, Integrated Master of Science) 10799 Food Process Engineering (4 Years, Bachelor of Technology) 11208 Life Science (5 Years, Integrated Master of Science) 11814
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