What is the minimum cutoff for B.A. LL.B. (Hons.) at Chanakya National Law University, Patna?
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2 Answers
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The minimum cutoff for B.A. LL.B. (Hons.) at Chanakya National Law University (CNLU) in Patna is 1314 for General Category students.
The minimum cutoff for BBA LLB (Hons.) is 1218 for General Category students.
The eligibility criteria for B.A. LL.B. (Hons.) at CNLU are:
10+2 with a minimum of 45% marks
CLAT
The eligibility criteria for BBA LLB (Hons.) at CNLU are:
Graduate with a minimum of 45% marks
CLAT
The cut off for CNLU in 2021 was:
45% for Unreserved/OBC/Specially Abled Persons (SAP) and other categories
40% for Scheduled Caste/Scheduled Tribe (SC/ST) categories
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The opening rank required for NLU Patna is 1314 in BA. LLB (Hons). For General category it is 1218 under the Vertical Reservation of Fifth Provisional Allocating List.
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