What is the minimum cutoff for B.Tech at COER University, Roorkee 2023?
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1 Answer
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The minimum cutoff for Bachelor of Technology at COER University, Roorkee, for the academic year 2023-24 is a minimum of 50 percentile in the closing rank, which is near about 50,000. Additionally, candidates must have at least 45% in 10+2 with Physics, Mathematics, and Chemistry/Biotechnology/Biology. Additionally, the university's cutoff for Bachelor of Technology admission is based on 10+2 merit, not Joint Entrance Examination Main.
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