What is the minimum cutoff for B.Tech at GNIT IPU 2023?
-
2 Answers
-
The minimum cutoff for B.Tech at GNIT IPU 2023 depend on the branch and category of submission of application form .
According to one report of article The cutoff for various courses of B.Tech at Greater Noida Institute of Technology is following:
B.Tech Information Technology: 618, 890
B.Tech Computer Science Engineering: 263591, 239238, 240479
To be eligible for B.Tech at GNIT Greater Noida, you must:
Pass 12th Class of 10+2 of CBSE or equivalent with a minimum of 50% marks in aggregate
Pass in English
For B Tech Computer Science Engineering in Greater Noida, you must:
Pass Diploma in Engineering or B.Sc.
...more -
The minimum cutoff for B.Tech at GNIT IPU 2023 varies depending on the branch and category. Here are some cutoffs for 2023:
B.Tech (Lateral) Information Technology: 618, 890
B.Tech Computer Science Engineering: 263591, 239238, 240479
To be eligible for B.Tech at GNIT Greater Noida, you must:
Pass 12th Class of 10+2 of CBSE or equivalent with a minimum of 50% marks in aggregate
Pass in English
For B Tech Computer Science Engineering in Greater Noida, you must:
Pass Diploma in Engineering or B.Sc. with Mathematics
Have an aggregate of 45% for General Category or 40% for SC/ST Category
Related Questions
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 63k Colleges
- 966 Exams
- 616k Reviews
- 1450k Answers
