What is the minimum cutoff for B.Tech at JUIT Solan 2023?
Asked by Nishar Ahmed
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1 Answer
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The minimum eligibility criteria for B.Tech admission at Jaypee University of Information Technology (JUIT) in 2023 are as follows:
- Candidates must have completed their 10+2 (or equivalent) with a minimum of 60% aggregate marks to be eligible for admission to B.Tech programs.
- Candidates must have appeared in JEE Main 2023 or CUET (UG) 2023 conducted by JUIT.
- The cutoff for different branches of B.Tech may vary depending on the availability of seats and the number of applicants. The cutoff for CSE branch goes around 1.6 Lakh, for IT and ECE it goes around 2.5 Lacs and for civil it goes for around 5 Lakh.
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