What is the minimum cutoff for B.Tech at UPES School of Computer Science 2023?
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1 Answer
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Here's some information about the 2023 cutoff at the University of Petroleum and Energy Studies (UPES) School of Computer Science:
- The minimum cutoff for the UPESEAT entrance exam is 60%.
- Applicants who take the JEE Mains must score at least 70% and have scored 80% in their 12th or equivalent exam.
- Applicants for the B.Tech CSE course at UPES must meet the following eligibility requirements:
- Have a JEE rank as specified by the cut-off
- Have an SAT score of above 50 percentile
- Have at least 80% marks at the higher and senior secondary levels
- Have at least 80% aggregate in PCM Physics, Chemistry, and Mathematics at the senior secondary level&nbs
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Yes, the eligibility criteria includes a minimum of 50% of marks in both 10th and 12th and a minimum of 50% in Physics, Chemistry and Maths. For selection, you will have to qualify in the UPESEAT exam to apply for B.Tech CSE couse. However, scores from national level engineering exams like JEE are also accepted, so students can give JEE or UPESEAT entrance exam.
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