What is the minimum cutoff for IIIT Delhi BTech in CSE course?
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1 Answer
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The minimum cutoff rank required for IIIT BTech in CSE admission during the Round 1 admission was 7429 or less for the students belonging to the General AI quota. Students with lower cutoff ranks will have the better chance of securing admission to CSE at IIIT Delhi. The institute offers multiple CSE specialisations, for which the JAC Delhi Round 1 closing ranks for the general AI quota students are tabulated below:
Course JAC Delhi Round 1 Cutoff 2025 (General AI Quota) B.Tech. in Computer Science and Economics 7429 B.Tech. in Computer Science and Design 9594 B.Tech. in Computer Science and Social Science 13365 B.Tech. in Computer Science and Biosciences 16098 B.Tech. in Computer Science and Engineering 19158 B.Tech. in Computer Science and Applied Mathematics 20194 B.Tech. in Computer Science and Artificial Intelligence 29567
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