What is the minimum cutoff for Techno India University TNJEE cutoff 2023 for B.E. in Computer Engineering?

16 Views|Posted 2 years ago
Asked by Shrooti Jain
3 Answers
D
2 years ago

Round 3 cutoff for  WBJEE 2023  at Techno India University is 42319 to 95816.  The closing ranks for all B.Tech.programs ranged from 42319 to 95816. The favourite computer Science and engineering, closed with a rank of 42319.
An alternative to WBJEE is  JEE Mains  which is also the way to get a seat

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Y
2 years ago

The WBJEE 2023 cutoff for Round 3 at Techno India University has been released. According to the Techno India University cutoff for Round 3 in 2023, the closing ranks for all B.Tech. specializations ranged from 42319 to 95816. The most competitive specialisation has been computer Science and enginee

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V
2 years ago

89555 is the minimum cutoff for Techno India University TNJEE cutoff 2023 for B.E. in Computer Engineering.

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Techno India University Powered by Emversity does not mention any information regarding BSc (hons) fee refunds for cancelling the admissions.

Generally, Emversity does not offer refunds of any kind under any circumstances for the fees paid by a student towards their chosen course.

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Candidates will need to provide copies in the appropriate forms of the below mentioned documents to complete the Techno India University Powered by Emversity BSc (hons) admission process:

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Techno India University Powered By Emversity offer four-year long BSc course in two specialisations such as BSc in Anaesthesia and Operation Theatre Technology (A&OTT) and BSc in Cardiovascular Technology (CVT). 

 

 
 
 
 
 

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Techno India University Powered by Emversity offers a total of 240 seats in BSc progarmme. The seats are divided in two specialisations as:

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This is taken from the official website of college. It may change.

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