What is the minimum cutoff for Techno India University TNJEE cutoff 2023 for B.E. in Computer Engineering?
-
3 Answers
-
Round 3 cutoff for WBJEE 2023 at Techno India University is 42319 to 95816. The closing ranks for all B.Tech.programs ranged from 42319 to 95816. The favourite computer Science and engineering, closed with a rank of 42319.
An alternative to WBJEE is JEE Mains which is also the way to get a seat at Techno India University for computer science. The overall cutoff for JEE-Mainis 89555–295479. If you want to tke admission the a rank under 90k will work. -
The WBJEE 2023 cutoff for Round 3 at Techno India University has been released. According to the Techno India University cutoff for Round 3 in 2023, the closing ranks for all B.Tech. specializations ranged from 42319 to 95816. The most competitive specialisation has been computer Science and engineering, with a closing rank of 42319.
On the other hand, JEE Mains is also the way to get a seat at Techno India University for computer science. The overall cutoff can be summarized for JEE-Main as 89555–295479 all- 295479 ALL INDIA general rank. Thus, by 2023 estimates, a candidate would need a rank of around 85000 to 90000 to be on the...more -
89555 is the minimum cutoff for Techno India University TNJEE cutoff 2023 for B.E. in Computer Engineering.
Related Questions
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 63k Colleges
- 963 Exams
- 608k Reviews
- -50000 Answers
