What is the minimum mark or rank required in JEE Main to get a seat in the IT department of AIT Pune?

0 70 Views | Posted a year ago
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  • Shiksha Ask & Answer

    Answered by

    Janki H Gajjar | Contributor-Level 10

    6 months ago

    AIT Pune cutoff for admission to the BE course was concluded after Round 1 of JEE Main Seat Allotment result in 2019. Considering the AIT Pune closing ranks for BE since 2019, candidates can expect closing rabks for BE to range between 53637 and 113592 for General category. Going as per cutoff 2019, JEE Main Round 1 Seat Allotment, the closing rank for AIT Pune B.E. in Information Technology was 65295. Hence, candidates with the range of rank upto 65295 can apply for AIT Pune IT Department. For more details regarding AIT Pune cutoff, click here

  • R

    Answered by

    Ritu Rathee | Contributor-Level 8

    a year ago

    The minimum mark or rank required in JEE Main to get a seat in the IT department of AIT Pune depends on the category and the counselling round of the admission process. According to the web search results, the closing rank for the IT department of AIT Pune in the final round of JEE Main 2023 counselling was 67582. However, this rank may vary every year depending on the number of applicants, the difficulty level of the exam, and the availability of seats. You can check the previous years' cutoffs and the current year's updates on the official website of AIT Pune or the JEE Main website.

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