What is the minimum rank required to get a call from IIT Delhi?
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2 Answers
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The minimum rank needed for admission to IIT Delhi varies by course, year, and other factors. For the Computer Science and Engineering (CSE) programme, the typical JEE Advanced rank required is between 90 and 1201, influenced by applicant numbers, exam difficulty, and seat availability. For the CAT exam, a qualifying percentile of 90 is required, but the cutoff for a Personal Interview (PI) call is usually around 98. Additionally, the opening and closing ranks differ based on candidate categories and quotas, such as differences between female candidates and the general category.
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To get into IIT Delhi for MSc admission, IIT JAM scores (ranks) are considered. The IIT Delhi JAM Cutoff 2024 was concluded for MSc courses for different categories under the AI category. For the General AI category candidates, the closing ranks for MSc courses ranged between 32 and 541. Candidates can check the IIT Delhi MSc cutoff 2024 in the table below:
Course 2024 M.Sc. in Physics 157 M.Sc.1 in Chemistry 108 M.Sc. in Mathematics 173 M.Sc. in Economics 32 M.Sc.in Biological Sciences 541
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