What is the MPBSE 12th cutoff for Jai Narain college of Technology (JNCT)?
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1 Answer
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To be eligible for admission to the BE/BTech course at Jai Narain College of Technology (JNCT), the candidate has to score a minimum of 45% aggregate in class 12 in a relevant stream from any recognised board, including the CBE, ISC, or MPBSS. Eligible students will have to appear for either the JEE Mains or the MPPET exam and score valid marks to be eligible for the course.
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For Global Engineering and Management College in Jabalpur, the MPBSE 12th cutoff applied during MP DTE counselling aligns with JEE Main seat allocation. The general category closing ranks for B.Tech courses in 2023 were:
• Civil: 565,670
• ECE: 861,396
• CSE/Data Science/IT: around 818,229? –?828,603
3 month me clear krne hoga app mujhe sahayata kar skte ho me to abhi padhi nhi kiya he but app mujhe Keh Skt ho kese padhai karu jese 70 percent above ayega
Class 12th cutoff of this institute is 45% marks for general category candidates and 40% for SC/ST/OBV candidates with physics, chemistry, and mathematics.
Better writing plays a crucial role in performing better in the MPBSE 12th board exams. To improve writing skills, the students should practice writing answers in each subject every day. They should also focus on writing clear and point-to-point answers. Also, the students should try to write simple answers.
If you feel stressed while preparing for MP Board 12th exams, take a short break and do something that relaxes your mind like listening to music or going for a walk. Talk to your family or friends about how you feel. Avoid comparing your preparation with others. Practice meditation or deep breathing to stay calm. Remember, regular revision and smart work can reduce stress.
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