What is the NIT Mizoram JEE Main cutoff 2025 for OBC?

7 Views|Posted a month ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Neerja Rohatgi | Contributor-Level 10

a month ago

NIT Mizoram BTech cutoff 2025 for the OBC AI category ranged from 10144 in the first round to 118197 in the last round. For the OBC HS quota, the cutoff was only released for the BTech CSE course. The cutoff in the first and last round was 349722.

Candidates can refer to the table below to view the

Upvote

Similar Questions for you

What is the I2IT Pune JEE Main cutoff for Computer Engineering?

Neerja Rohatgi

The I2IT Pune JEE Main cutoff 2025 was released in the form of ranks for the All India categories. For the General AI category, the BE in the Computer Engineering branch had the overall cutoff ranging from 42136 in the first round to 52834 in the last round. Hence, General AI students needed to

Neerja Rohatgi

The selection process for the All India quota students is based on their JEE Main ranks. Students who want admission to I2IT Pune need to appear in the CAP counselling process to avail a seat for any BE course.

The minimum rank required for admission was 68635 for the General AI category. Hence

Neerja Rohatgi

The minimum rank required to get admission at I2IT Pune would depend on the category you belong to. The I2IT Pune JEE Main cutoff 2025 for the General AI category says that a rank of at least 61370 is required to be eligible for admission to the BTech in Information Technology department. This

Neerja Rohatgi

Students who attempted the JEE Main should start preparing for the JEE Advanced entrance examination if they want admission at IITs. Those who score above the 98^th percentile in JEE Main session 2 should start to study for the JEE Advanced exam.

Students who get around the 95^th and 98^th &

Chanchal Pandey

As of now, the easiest shift of JEE Main 2026 April session was the April 2 shift 1 exam.