What is the selection criteria for admission to the BTech programme at NIT Surathkal?
The NITK Surathkal BTech programme accepts students based on their JEE Main score and JoSAA Counselling. In the event that seats remain unfilled following JoSAA counselling, CSAB counselling is used to fill them. In addition, candidates need to fulfil the minimal requirements, which include a minimu
The admission procedure for the BTech programme at NIT Surathkal primarily involves the Joint Entrance Examination (JEE) Main. Candidates must first qualify for the JEE Main, a national-level exam conducted by the National Testing Agency (NTA). Based on their JEE Main scores, candidates participate
The Admission criteria in NIT Surathkal for BTech is Class 12 with 75% aggregate with the qualifying marks in JEE Main, DASA UG, CSAB + JoSAA counseling.
For an MBA, the candidate should Graduate with 50% aggregate and MAT, CAT, GATE + GD & PI.

Admission to the BTech programme at NITK Surathkal is done basis of JEE Main score and JoSAA Counselling. If the seats are left vacant after JoSAA counselling, then the seats are filled out through CSAB counselling. Apart from this, applicants must meet the minimum eligibility as well, which is at l
Similar Questions for you
Yes, it is easy to apply for various courses at the National Institute of Technology Surathkal. Students just have to go to the institute's official website to apply. The admission is through many entrance tests for specific courses.
National Institute of Technology or NIT Surathkal is in Karnataka and was established in 1960. It has 13 departments, 1 School, and 12 supporting centres. NIT Surathkal gives UG, PG and PhD courses in the areas of Engineering, Management, and Science.
NIT Surathkal BTech cutoff 2025 was 3934 in round 1 for the General AI category, which later increased to 5316 in last round for the BTech ECE course. Students can refer to the table below to know the overall cutoff range for all other All India categories.
| All India Category | JEE Main Cutoff Range 2025 |
|---|---|
| General | 3934 - 5316 |
| OBC | 1687 - 7933 |
| SC | 808 - 888 |
| ST | 459 - 459 |
| EWS | 599 - 6196 |
Please note that other quotas, catego
NIT Surathkal CSE cutoff 2025 for the General AI category female students was 3531 in the round 1, which later increased to 4892 in the last round. For the OBC AI category female candidates, the overall cutoff ranged from 1723 to 1792. Students should know that other categories and quotas will
Students who belong to the General AI category need to secure a rank between 1528 and 2158 to be eligible for BTech CSE branch. On the other hand, the OBC AI category students need a rank between 495 and 3690. Please note that other categories will have different cutoffs accordingly.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Most viewed courses
Didn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering